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Edexcel C3,C4 June 2013 Thread

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Original post by Converse girl
hi guys can you help me out iam having trouble intergratiting sec^2xtanx


You could do it by substitution or, more quickly, by recognition. There are two possible answers for this, btw, there's just a different constant for both answers. :smile:
(edited 11 years ago)
Original post by justinawe
use the substitution u=sec2xu= \sec^2 x



Original post by brittanna
This is in the form f(x)f(x)f'(x)f(x). Try considering tan2(x)tan^2(x).



Original post by usycool1
You could do it by substitution or, more quickly, by recognition. There are two possible answers for this, btw, there's just a different constant for both answers. :smile:


i got sec^2x :redface:
Original post by Converse girl
i got sec^2x :redface:


+C

And you should have got (1/2)sec^2 x + C...what did you do to get that answer? :smile:
Original post by Converse girl
i got sec^2x :redface:


Close, but you forgot a part of it :tongue:

remember xn dx=xn+1n+1+C\displaystyle \int x^n \mathrm{ \ } dx = \frac{x^{n+1}}{n+1} + C
Reply 324
Original post by Converse girl
i got sec^2x :redface:


I got tan^2x/2 + c I used u=tanx someone confirm please
Original post by QwertyG
I got tan^2x/2 + c I used u=tanx someone confirm please


That's right too, just with a different constant. :yy:
Original post by usycool1
+C

And you should have got (1/2)sec^2 x + C...what did you do to get that answer? :smile:



Original post by justinawe
Close, but you forgot a part of it :tongue:

remember xn dx=xn+1n+1+C\displaystyle \int x^n \mathrm{ \ } dx = \frac{x^{n+1}}{n+1} + C


oh yeah i get it always forget +C

thanks guys
i need a lot of practice with intergration :stomp:
Reply 327
Original post by usycool1
That's right too, just with a different constant. :yy:


If you done it with substitution would you have used u=tanx or u=sec^2x?
Original post by QwertyG
If you done it with substitution would you have used u=tanx or u=sec^2x?


I would have used u=tanxu= \tan x looking at the question properly. I said u=sec2xu = \sec^2 x earlier but wasn't really thinking, the former would have been much easier.
Original post by usycool1
+C

And you should have got (1/2)sec^2 x + C...what did you do to get that answer? :smile:


I see what you mean now! I used integration by parts 3 times and still continues:s-smilie:
Original post by otrivine
I see what you mean now! I used integration by parts 3 times and still continues:s-smilie:


By parts 3 times?!! :eek:
Original post by otrivine
I see what you mean now! I used integration by parts 3 times and still continues:s-smilie:


Here's how you can do it (solution in spoiler):

Spoiler

Original post by usycool1
Here's how you can do it (solution in spoiler):

Spoiler


I lost what was going on after line 2 :s-smilie:

Oh wait never mind i get it :smile:
(edited 11 years ago)
how far is evryone through c3 and c4 revision?
Original post by usycool1
Here's how you can do it (solution in spoiler):

Spoiler




wow! wait, can i now just use substitution, my integration by parts was the same as urs but do not get then how you or why you considered I?:confused:
Original post by otrivine
wow! wait, can i now just use substitution, my integration by parts was the same as urs but do not get then how you or why you considered I?:confused:


Its quite unlikely to come up if you ask me - I don't think it has ever before... where did you get the question from ?
Original post by posthumus
Its quite unlikely to come up if you ask me - I don't think it has ever before... where did you get the question from ?


Usycool1 asked this question and I was trying to solve it!

By the way on page on differenitation example 4! I think they made a mistake ,can you or anyone confirm this.

The question was

find the valie of dy/dx at point (1,1)

where 4xy2 +6x2/y = 10
Original post by otrivine
Usycool1 asked this question and I was trying to solve it!

By the way on page on differenitation example 4! I think they made a mistake ,can you or anyone confirm this.

The question was

find the valie of dy/dx at point (1,1)

where 4xy2 +6x2/y = 10

I checked it, looks right to me
Original post by otrivine
Usycool1 asked this question and I was trying to solve it!

By the way on page on differenitation example 4! I think they made a mistake ,can you or anyone confirm this.

The question was

find the valie of dy/dx at point (1,1)

where 4xy2 +6x2/y = 10


What answer did you get ?
Original post by raiden95
I checked it, looks right to me


they got 12x/y but should there not be a y with 12x?

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