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ocr a f325 revision thread

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Original post by MathsNerd1
Just a warning, at 9 I'll do some unit 1 stuff again.

Entropy is the quantitative measure of the degree if disorder in a system.


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Oh no :frown:

correct! my turn
Original post by otrivine
Oh no :frown:

correct! my turn


It's fine cause if we do this at least 2 hours a day thing and just keep alternating then that'll be some great revision for me, but unit 1 is first so I need to focus more on that right now :smile:

Okay:
Explain the properties of transition metal compounds (4)
Also define a transition element (1)

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Original post by MathsNerd1
It's fine cause if we do this at least 2 hours a day thing and just keep alternating then that'll be some great revision for me, but unit 1 is first so I need to focus more on that right now :smile:

Okay:
Explain the properties of transition metal compounds (4)
Also define a transition element (1)

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sure!

1) catalysts, coloured compounds, variable oxidation states and are metals which are hard. Have partially filled d sub shells

2) one or more ion with a partially filled d sub shell
Original post by otrivine
sure!

1) catalysts, coloured compounds, variable oxidation states and are metals which are hard. Have partially filled d sub shells

2) one or more ion with a partially filled d sub shell


Correct!


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Give the half equations and full balanced equation (overall) when titrating between mangangate and when Fe3+ is reduced to Fe2+ (4)
Original post by otrivine
Give the half equations and full balanced equation (overall) when titrating between mangangate and when Fe3+ is reduced to Fe2+ (4)


It'll be easier posting the picture instead of writing it all out.


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Original post by MathsNerd1
It'll be easier posting the picture instead of writing it all out.


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Perfect!!

my turn
Original post by otrivine
Perfect!!

my turn


Okay, 1 more each then I'm onto the other unit. Here's yours

Question 7 if it wasn't already obvious :smile:


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Original post by MathsNerd1
Okay, 1 more each then I'm onto the other unit. Here's yours

Question 7 if it wasn't already obvious :smile:


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that took quite long!

ok

1) 8H+ + MNO4- + 5e- --> Mn2+ + 4h2o

2) 6H+ + 5(COOH)2 + 2MNO4 - ---> 10CO2 +2Mn2+ + 8H20

3) concentration = 0.03 mol dm-3
Original post by otrivine
that took quite long!

ok

1) 8H+ + MNO4- + 5e- --> Mn2+ + 4h2o

2) 6H+ + 5(COOH)2 + 2MNO4 - ---> 10CO2 +2Mn2+ + 8H20

3) concentration = 0.03 mol dm-3


That's all correct! Last one for me now :smile:


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Original post by MathsNerd1
That's all correct! Last one for me now :smile:


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ok

For each of the unbalanced redox equations below:

a) MnO4- + U3+ Mn2+ + UO2+ in aqueous acid (H+ present) conditions
b) Cr2O72- + C2O42- CO2 + Cr3+ in aqueous acid (H+ present) solutions

(i) Identify which species is the oxidizing agent and which is the reducing agent.

(ii) Write the balanced half-equations for the oxidation half reaction and the reduction half reaction

(iii) Balance the redox equation
(12 marks)
Original post by otrivine
ok

For each of the unbalanced redox equations below:

a)MnO4- + U3+ Mn2+ + UO2+ in aqueous acid (H+ present) conditions
b)Cr2O72- + C2O42- CO2 + Cr3+ in aqueous acid (H+ present) solutions

(i) Identify which species is the oxidizing agent and which is the reducing agent.

(ii) Write the balanced half-equations for the oxidation half reaction and the reduction half reaction

(iii) Balance the redox equation
(12 marks)


Oh how kind are you! This might take a while and I'm still eating to I could be some time, just check back again in about 30 minutes :tongue:


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Original post by MathsNerd1
Oh how kind are you! This might take a while and I'm still eating to I could be some time, just check back again in about 30 minutes :tongue:


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hahahaha , thank you, I am an examiner :colone:
Original post by otrivine
ok

For each of the unbalanced redox equations below:

a)MnO4- + U3+ Mn2+ + UO2+ in aqueous acid (H+ present) conditions
b)Cr2O72- + C2O42- CO2 + Cr3+ in aqueous acid (H+ present) solutions

(i) Identify which species is the oxidizing agent and which is the reducing agent.

(ii) Write the balanced half-equations for the oxidation half reaction and the reduction half reaction

(iii) Balance the redox equation
(12 marks)


Okay I think this is correct for the first one. I'm getting slightly stuck on the half equation part of the second one though :-/




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Original post by otrivine
hahahaha , thank you, I am an examiner :colone:


What do I do next as I don't see how I can remove the second carbon molecule :-/


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Original post by MathsNerd1
What do I do next as I don't see how I can remove the second carbon molecule :-/


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Okay , tomorrow I will send an attachment with the correct solutions :smile:

yup you are correct by the way regarding the first equationm
Original post by otrivine
Okay , tomorrow I will send an attachment with the correct solutions :smile:

yup you are correct by the way regarding the first equationm


Okay, thanks and I'm glad I at least got the first one correct, I also apologise about my handwriting as I assume you struggled reading it? Most people tend to :tongue: And I'm now determined to work this thing out! Forget unit 1 now, I'm completing this first.


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Original post by MathsNerd1
Okay, thanks and I'm glad I at least got the first one correct, I also apologise about my handwriting as I assume you struggled reading it? Most people tend to :tongue: And I'm now determined to work this thing out! Forget unit 1 now, I'm completing this first.


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:smile: hahaha no worries!

do it then ill mark :smile:
Original post by otrivine
:smile: hahaha no worries!

do it then ill mark :smile:


Hmm, do you have a list of redox equations like this to help give me some more practice to be able to build up to this? I'm confused how a carbon molecule can be removed, can methane be produced by it or isn't that possible?


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Original post by MathsNerd1
Hmm, do you have a list of redox equations like this to help give me some more practice to be able to build up to this? I'm confused how a carbon molecule can be removed, can methane be produced by it or isn't that possible?


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Not really, ok I will do a lot of examples for you!

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