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C1 Graphs help?

I'm drawing graphs, and there are two equations:

1) y = x (x + 1) (x - 1)
2) y = x (x + 1 ) (1 - x)

They both give the same points where it crosses the x axis (0,0) (-1,0) and (1,0) however the answers say that the graphs are different in the way the graph actually goes through the points. Here's a picture to show what I mean

ImageUploadedByStudent Room1365014692.721639.jpg

It's a poor quality picture, sorry! Anyway, my question is, how do I determine how the line going through the points goes? Because as seen in the two diagrams in the image, they're kind of mirror images of each other and I don't get where that comes from.


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Original post by JodieW
I'm drawing graphs, and there are two equations:

1) y = x (x + 1) (x - 1)
2) y = x (x + 1 ) (1 - x)

They both give the same points where it crosses the x axis (0,0) (-1,0) and (1,0) however the answers say that the graphs are different in the way the graph actually goes through the points. Here's a picture to show what I mean

ImageUploadedByStudent Room1365014692.721639.jpg

It's a poor quality picture, sorry! Anyway, my question is, how do I determine how the line going through the points goes? Because as seen in the two diagrams in the image, they're kind of mirror images of each other and I don't get where that comes from.


Posted from TSR Mobile


Yes, but the (1-x) throws a twist into the tale. Can you see why? If not, expand the brackets :smile:
Reply 2
Original post by Indeterminate
Yes, but the (1-x) throws a twist into the tale. Can you see why? If not, expand the brackets :smile:


Oh okay, so the second one was the negative of the first one, so is it because it has that negative sign that the line of the graph goes in that direction?



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Original post by JodieW
Oh okay, so the second one was the negative of the first one, so is it because it has that negative sign that the line of the graph goes in that direction?



Posted from TSR Mobile


Yep, multiplication by a negative flips it the other way up :smile:
Reply 4
Original post by Indeterminate
Yep, multiplication by a negative flips it the other way up :smile:


Oh I see, thanks! :smile:


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Reply 5
Original post by Indeterminate
Yep, multiplication by a negative flips it the other way up :smile:


Hey, sorry to bother you again, but I'm having another issue with graphs :smile:

Say I have an x^3 graph that goes through (0,0) and (1,0), how do I know whether to draw it like this:

ImageUploadedByStudent Room1365113936.567801.jpg

Or this:

ImageUploadedByStudent Room1365113978.372494.jpg

It really confuses me, is there something I don't know that tells me whether or not the graph touches the point or actually goes through it? The curve is y = x (x - 1)^2 by the way. Could you help me please? :smile: Thank you!


Posted from TSR Mobile
Original post by JodieW
Hey, sorry to bother you again, but I'm having another issue with graphs :smile:

Say I have an x^3 graph that goes through (0,0) and (1,0), how do I know whether to draw it like this:

ImageUploadedByStudent Room1365113936.567801.jpg

Or this:

ImageUploadedByStudent Room1365113978.372494.jpg

It really confuses me, is there something I don't know that tells me whether or not the graph touches the point or actually goes through it? The curve is y = x (x - 1)^2 by the way. Could you help me please? :smile: Thank you!


Posted from TSR Mobile


Well, a graph touches the x axis at a point if it has a double (or higher) root there.

So

f(x)=x2(x1)f(x)=x^2(x-1)

would touch the x axis at x=0, but then would go through x=1 as normal.

So what can you say about your graph? :smile:
(edited 11 years ago)
Reply 7
Original post by JodieW
Hey, sorry to bother you again, but I'm having another issue with graphs :smile:

Say I have an x^3 graph that goes through (0,0) and (1,0), how do I know whether to draw it like this:

ImageUploadedByStudent Room1365113936.567801.jpg

Or this:

ImageUploadedByStudent Room1365113978.372494.jpg

It really confuses me, is there something I don't know that tells me whether or not the graph touches the point or actually goes through it? The curve is y = x (x - 1)^2 by the way. Could you help me please? :smile: Thank you!


Posted from TSR Mobile


You can just stick in x = 1/2 and see what the y value is. Although you should understand why it is like that, with the post above
(edited 11 years ago)
Reply 8
Original post by Indeterminate
Well, a graph touches the x axis at a point if it has a double (or higher) root there.

So

f(x)=x2(x1)f(x)=x^2(x-1)

would touch the x axis at x=0, but then would go through x=1 as normal.

So what can you say about your graph? :smile:


Is it that simple? Thanks, I'm relieved that I finally know now haha :smile:


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