V = pd across the external circuit (V) E = emf of the cell (V) I = current through the cell (A) r = value of the internal resistance (Ω ) (Ir = the p.d. across the internal resistor)
V = E - Ir 2.04 = E - (Ir) 2.04 = E - (2.08x0.98) 2.04 = E - 2.0834 E = 2.04 + 2.0834 E = 4.1234
I have no idea if that's right... I managed to grab an A in Physics but that was over 7 years ago haha!
Maybe there is no internal resistance? Do you have resistance in each wire? Do you have overall current? Work out total resistance in parallel, then use E=IR
I'm not 100% sure this is correct, but after i left the exam in january I wish i did this.
EDIT: sorry about the mistake, the internal resistance is in the copper wire i believe, and the total internal resistance 1/r = 1/0.98 + 1/0.98 is it not?
Let me know how you do, that's how I think its done my answer is 3.06V or 13.0V, do you know the answer?
Maybe there is no internal resistance? Do you have resistance in each wire? Do you have overall current? Work out total resistance in parallel, then use E=IR
I'm not 100% sure this is correct, but after i left the exam in january I wish i did this.
EDIT: sorry about the mistake, the internal resistance is in the copper wire i believe, and the total internal resistance 1/r = 1/0.98 + 1/0.98 is it not?
Let me know how you do, that's how I think its done my answer is 3.06V or 13.0V, do you know the answer?
The answer is 16.1v and the solution is that they do:
The lamp is working at rated capacity so you've got 12v across the bulb and 2.04v across each of the two wires connecting it to the power supply. Seems straightforward tbh.
Haha thats weird, i said 3.06 or 13.0 add them its 16.06 which is 16.1 1dp
There is 12V across the source, as stated in the question. Then, visualise the circuit, paying particular attention to the way that the wires are organised (parallel/series). Then use the appropriate circuit rules to work out the total emf, which is the solution as given. I did this paper in January and got above 90%.
There is 12V across the source, as stated in the question. Then, visualise the circuit, paying particular attention to the way that the wires are organised (parallel/series). Then use the appropriate circuit rules to work out the total emf, which is the solution as given. I did this paper in January and got above 90%.
Haha same! I got 94% but if i got this question right would have been better!
90% and 94% that is amazing, what tips could you give me in order to get that? I got 55/70 which was 1 mark of an A which was annoying, I found out I got full marks in the quantum and particles bit and totally messed up in the electristy bit
90% and 94% that is amazing, what tips could you give me in order to get that? I got 55/70 which was 1 mark of an A which was annoying, I found out I got full marks in the quantum and particles bit and totally messed up in the electristy bit
Same really, had full marks up till Q4, lost 2 marks on the question above, other 4 here and there worded questions. Tips would be just make sure you really understand everything going on in a circuit, I myself didn't completely know which is why i lost marks