Trigonometry question

Solve the equation 2sin^2theta = costheta + 2 for values between 0 and 360 degrees.

So the identities are:

sin^2theta + cos^2theta

tantheta=sintheta/costheta


Any help as to how this can be solved would be very much appreciated, thanks
And sorry for the lack of the use of latex!

You want a quadratic in cos

$\sin^2 \theta + \cos^2 \theta = 1$

You're both analogous to Speedy Gonzales

What do you mean by that?

So far I've got:

2(1-cos^2theta)=costheta +2
2-2cos^2theta=costheta +2
-2cos^2theta=costheta

Where do I go after that?

I'm sorry, but what?

I'm sorry, but what?

Nevermind, I was referring to Indeterminate and Mr M xD In response to your last question, you have a quadratic in costheta, solve how you normally would

He means that we were too quick (comparison to speedy gonzales)

Oh I see.

And I have no idea what you mean by that.

costheta +2cos^2theta=0
costheta(1+2costheta)=0

But how would that help me in any way?

Oh I see.

And I have no idea what you mean by that.

costheta +2cos^2theta=0
costheta(1+2costheta)=0

But how would that help me in any way?

ab = 0 means a = 0 or b = 0

Arriba! Arriba!

And again! xD

I see what you meant by MrM now, I hadn't a clue who he was.

You have $\cos \theta (1 + 2 \cos \theta ) = 0 \Rightarrow \cos \theta = 0$ or $\cos \theta = -\frac{1}{2}$

My fame precedes me.

Oh yeah. Funny how I didn't see that, thanks

It's annoying how you know the answer to every maths question though :P