Logarithms

(ii) Solve the equation

4^x-3(2^(x+1))=0

So what I did is

(2^x)^2-6(2^x)=0

2^x(2^x-6)=0

-2^x | 6

How do I go on from here?

Right idea but something went awry at the end of your solution.

4^x-3(2^{x+1})=0

2^{2x}-6(2^x)=0

2^x(2^x-6)=0

This is all good. Now solve.

We last had this question a couple of days ago.

Here it is.

(edited 11 years ago)

Right idea but something went awry at the end of your solution.

4^x-3(2^{x+1})=0

2^{2x}-6(2^x)=0

2^x(2^x-6)=0

This is all good. Now solve.

We last had this question a couple of days ago.

Here it is.

Cheers, I didn't realise that I have to equal 2^x=6. Got the solution.

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