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electricity power question

http://www.scribd.com/mobile/doc/50654250?width=768

I'm stuck on question 4. The correct answer is B.
P=IV
V=IR

So P=I2R

If the new lamp has twice the resistance, it has to have twice the power. So WHY isn't the correct answer C? I need an explanation so I can understand why B is right and not C.

Thank you
Reply 1
Voltage is constant at 230V.

P=IV. P=VI
V=IR therefore V/R=I so P=V^2/R
Double R, half the power
Reply 2
Original post by pratstercs
Voltage is constant at 230V.

P=IV. P=VI
V=IR therefore V/R=I so P=V^2/R
Double R, half the power


I guess it is better to substitute I=V/R into P=VI.

Thanks a lot.
Reply 3
Original post by krisshP
I guess it is better to substitute I=V/R into P=VI.

Thanks a lot.


It's not necessarily better, you just need to remember that the current will change as the resistance changes
Reply 4
Original post by pratstercs
It's not necessarily better, you just need to remember that the current will change as the resistance changes


Thanks

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