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integration by parts

Use integration by parts to integrate t *lnt with limits t=k and t=1


I did
u=ln t
du/dt = 1.t
dv/dt = t
v=1

so [lnt *1] - integrate 1 *(1/t) dt
then insert in limits t=k and t=1

but it didn't come to the answer of (1/2k^2) * lnk - 1/4k^2 + 1/4

the question also says k is positive.
Reply 1
Original post by 0utdoorz

dv/dt = t
v=1


This is not correct.
Original post by 0utdoorz
Use integration by parts to integrate t *lnt with limits t=k and t=1


I did
u=ln t
du/dt = 1.t
dv/dt = t
v=1

so [lnt *1] - integrate 1 *(1/t) dt
then insert in limits t=k and t=1

but it didn't come to the answer of (1/2k^2) * lnk - 1/4k^2 + 1/4

the question also says k is positive.


ddt(lnt)=1t\dfrac{d}{dt} (\ln t) = \dfrac{1}{t}

For n1n \neq -1

tn dt=1n+1tn+1+C\displaystyle \int t^n \ dt = \dfrac{1}{n+1}t^{n+1} + C
(edited 11 years ago)
Original post by notnek
Looking at the lines that follow, I'm thinking that error was a typo.


I edited my post to address the main issue :smile:

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