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Reply 1200
This is absolutely disgusting
Original post by zed963
This is absolutely disgusting

what?
Reply 1202
Original post by Bude8
You're well towards your way to a promotion, keep up the good work (y)


I'm sure you're being sarcastic there.
Reply 1203
Original post by MattFletcher
what?


That link that I just posted. It's about circumcision. Not the greatest topics of all I must admit but it's quite disgusting.
Original post by zed963
I'm sure you're being sarcastic there.


If you can't appreciate the boss's kindness then say goodbye to that promotion I was going to give you
Please don't ^

It's despicable :colonhash:
Reply 1206
Original post by Bude8
If you can't appreciate the boss's kindness then say goodbye to that promotion I was going to give you


Oooh, you're playing the take it or leave it game. What's the promotion anyway?
Original post by Bude8
I've got an iPhone 4S but I use it as if it's an iPod.


Foreveralone.jpg
Original post by zed963
This is absolutely disgusting


Original post by zed963
That link that I just posted. It's about circumcision. Not the greatest topics of all I must admit but it's quite disgusting.

Oh my god.:sick:
Reply 1209
Original post by zed963
This is absolutely disgusting


That's revolting
Reply 1210
Original post by L'Evil Fish
Please don't ^

It's despicable :colonhash:


Were you directing that to my post or Bude's post?
Original post by Elm Tree
Foreveralone.jpg


Nope.
WAR IS ETERNAL.
Original post by Vionar
No it's not! :puke:


have you even tried it?
Reply 1213
Original post by EduWiz
That's revolting


I agree.
Original post by zed963
Were you directing that to my post or Bude's post?


You obviously, L'Evil Fish knows that he shouldn't disrespect the boss.
Reply 1215
Original post by Bude8
Please try this question :smile:

The gravitational potential energy of an astronaut, mass , between the Earth and the moon is given by the equation:



When r=distance between the moon and the Earth.
When , the astronaut is equally attracted to the moon and the Earth. Find an expression for x when this occurs.




This is a nice problem, and it's differential; [-GMem/x^2]-[-GMmm/(r-x)^2]

However, when you equate this to zero you get an issue! You can never have a value of x for which you divide the constants by to get zero! 1/x can never equal zero!

So your graph shoots off to infinite! The solution looks something like this.. (assuming an 80kg astronaut)

graph.PNG
However, that would give a solution of around 6'800km. I'm not convinced your original equation was correct though.
The gravitational pull of something is equal to [GMobject]/r^2, so the point where the 2 attractions balance

[G*Me]/r^2=[G*Mm]/R^2

Given G and the Masses are constant you could solve for R like that.

This may all be rubbish, but just my ideas. Sorry if this wastes your time!
Reply 1216
Original post by Bude8
You obviously, L'Evil Fish knows that he shouldn't disrespect the boss.


Whos the boss
Original post by Bude8
Nope.
WAR IS ETERNAL.

And you say I'm weird :tongue:
Reply 1218
Original post by EduWiz
Whos the boss


Me. Zed has risen to take the throne.
Original post by MrGoogle
This is a nice problem, and it's differential; [-GMem/x^2]-[-GMmm/(r-x)^2]

However, when you equate this to zero you get an issue! You can never have a value of x for which you divide the constants by to get zero! 1/x can never equal zero!

So your graph shoots off to infinite! The solution looks something like this.. (assuming an 80kg astronaut)

graph.PNG
However, that would give a solution of around 6'800km. I'm not convinced your original equation was correct though.
The gravitational pull of something is equal to [GMobject]/r^2, so the point where the 2 attractions balance

[G*Me]/r^2=[G*Mm]/R^2

Given G and the Masses are constant you could solve for R like that.

This may all be rubbish, but just my ideas. Sorry if this wastes your time!


Woow looks complicated !! Is this even GCSE ? :tongue:

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