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Maths help?

solve each equation :
a)cos^2x+3sinx-3=0

b)3sin^2x-5cosx+2cos^2x=0

c)3sinx-2tanx=0d)4sin^2x-5sinx+2cos^2x=0

[h="1"]d)4sin^2x-5sinx+2cos^2x=0[/h]

(edited 11 years ago)

Reply 1

Slowbro93

What working out have you done so far?

Reply 2

Mr M

Study Forum Helper

Original post by hey_help

solve each equation :
a)cos^2x+3sinx-3=0

b)3sin^2x-5cosx+2cos^2x=0

c)3sinx-2tanx=0d)4sin^2x-5sinx+2cos^2x=0

[h="1"]d)4sin^2x-5sinx+2cos^2x=0[/h]

You are going to need to make use of the following identities:

\sin^2 x + \cos^2 x = 1

\sin 2x = 2 \sin x \cos x

\cos 2x = \cos^2 x - \sin^2 x

\displaystyle \tan x = \frac{\sin x}{\cos x}

(edited 11 years ago)

Reply 3

Felix Felicis

Original post by Mr M

You are going to need to make use of the following identities:

\cos 2x = \cos^2 x + \sin^2 x

Only joking :tongue:

Reply 4

Albino

Original post by Mr M

You are going to need to make use of the following identities:

\sin^2 x + \cos^2 x = 1

\sin 2x = 2 \sin x \cos x

\cos 2x = \cos^2 x - \sin^2 x

\displaystyle \tan x = \frac{\sin x}{\cos x}

Reply 5

Mr M

Study Forum Helper

Original post by Felix Felicis

Only joking :tongue:

Sorry!

Reply 6

Mr M

Study Forum Helper

Original post by Albino

Et tu Albino?

Reply 7

Albino

Original post by Mr M

Et tu Albino?

beaten to it by felix but ya me too :wink:

Reply 8

TenOfThem

Original post by Mr M

\sin^2 x + \cos^2 x = 1

darn

too slow to mock

serves me right for chatting on other fora

Reply 9

Mr M

Study Forum Helper

Original post by TenOfThem

serves me right for chatting on other fora

There are other fora?

:eek:

boom shakalaka

Original post by Mr M

There are other fora?

:eek:

You know about relationships now ... there are others too

I was engaged in a Degree Classification v Student Ranking discussion

Well exciting

Original post by upthegunners

\displaystyle x \neq \frac{1\pm 3\sqrt 5}{2}

???

Reply 14

upthegunners

Original post by Mr M

\displaystyle x \neq \frac{1\pm 3\sqrt 5}{2}

???

wrong thread :colondollar:

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