Hi guys,
The question i'm stuck on is about heating Cr(CO)6 and reacting it with Me2NCH2CH2NMe2
Cpd A is the product of this reaction and has MF C10H16CrN2O4
Furthermore, cpd A gives IR bands at 2007 cm-1, 1885cm-1, 1873 cm-1 and 1852 cm-1
I've gotten this far:
Heating Cr(CO)6 removes two CO groups to give Cr(CO)4 which has 2 free binding sites.
The IR bands say that there are both terminal CO groups and u2 bridging CO ligands (the u is meant to be mew).
So I've got all the pieces together, however I'm finding it hard to see how the Me2NCH2CH2NMe2 binds to the complex to give both the given IR data and the molecular formula - the only way Ive managed to get the molecular formula is to bind the free sites using the lone pair on the Nitrogens - however this gives an ionic cpd with only terminal CO ligands :/
Any help would be greatly appreciated!!
Thanks