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easiest method to solve this

t(3t44t215)=0t(3t^4-4t^2-15)=0

Easiest method to solve this?

Thanks.
(edited 11 years ago)
Reply 1
Try dividing by t (or is it l, cant seem to click on image). Should be able to see a recognisinle type of equation then. You should try substiution.

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Reply 2
Original post by alwayslast
Try dividing by t (or is it l, cant seem to click on image). Should be able to see a recognisinle type of equation then. You should try substiution.

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the mark seem suggests factoring to get t(3t2+5)(t23)=0t(3t^2+5)(t^2-3)=0

but I am not sure how they do this
Reply 3
Original post by upthegunners
t(3t44t215)=0t(3t^4-4t^2-15)=0

Easiest method to solve this?

Thanks.


As before divide by t. Then observe that this is a hidden quadratic
Hint:

Spoiler

Original post by upthegunners


Easiest method to solve this?

Thanks.


t=0

or

3t^4-4t^2-15=0

3t^4-4t^2=15

t^2(3t^2-4)=15


i dunno really
Original post by joostan
As before divide by t. Then observe that this is a hidden quadratic
Hint:

Spoiler



no u do no divide by t as u lose a solution t=0

do not listen to this op
Reply 6
Original post by upthegunners
the mark seem suggests factoring to get t(3t2+5)(t23)=0t(3t^2+5)(t^2-3)=0

but I am not sure how they do this


It's how you factorise any other quadratic eqation.
Reply 7
Original post by joostan
As before divide by t. Then observe that this is a hidden quadratic
Hint:

Spoiler



is letting say a=t2a=t^2 and solving a good idea? Then just subbing t2t^2 back in?
Reply 8
t(3t^4 - 4t^2 - 15)=0

3t^4 - 4t^2 - 15=0

t^2 = x

3x^2 - 4x - 15=0
(3x+5)(x-3) = 0
So, x= -5/3 or 3

therefore,
t^2= 3
t=Sqrt 3
Reply 9
Original post by Student#123
no u do no divide by t as u lose a solution t=0

do not listen to this op


The loss of the solution t = 0 only occurs if you don't write it down. It is the obvious solution, once written down, it's not a problem and you're left with a hidden quadratic.
Reply 10
Original post by upthegunners
is letting say a=t2a=t^2 and solving a good idea? Then just subbing t2t^2 back in?


Yes, don't forget that when you solve for t that there is a solution where t = 0
Let x = t^2 then solve as a quadratic


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