CCEA M1 13th May 2013

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Q1 P= 5.32N Q=10.5N
Q2 (i) u = 14.7 m/s
Q2 (ii) s = 11.0 m (3sf)

Q3 (i) 7120 N
Q3 (ii) Maximum number of people = 8
Q3 (iv) No air resistance. Treat lift as particle

Q4 (i) t = 3/2, 6 seconds
Q4 (ii) s = (2/3)t^3 - (15/2)t^2 + 18t metres
Q4 (iii) 31.6m

Q5 (i) v = 13 m/s
Q5 (ii) m = 4 or 12 kg

Q6 (ii) a = (6+8y) (y = coefficient of friction)
Q6 (iii) To get answer, use v = u + at, rearrange to get u = -(a)t = -(-8y - 6)T = (8y + 6)T

Q7 (ii) P = 48.3 N (3sf)
Q7 (iii) Q = 54.4N and 33.4 degrees

Anyone give feedback?????

Reply 41

jashfield730

Original post by Chriispy

Q3 (ii) Maximum number of people = 8

Just wondering how did you get 8?
did u round up from 7.52?

(edited 10 years ago)

Reply 42

TheSilentFez

Original post by Chriispy

For 5 i) v= -5ms^-1 because Impulse was -18Ns not 18Ns

Original post by jashfield730

Q3 (ii) Maximum number of people = 8

Just wondering how did you get 8?
did u round up from 7.52?

I got 8.3 something then rounded down to 8.
Then I scribbled this answer out in favour of a wrong one....

Reply 43

Chriispy

Original post by jashfield730

Q3 (ii) Maximum number of people = 8

Just wondering how did you get 8?
did u round up from 7.52?

Accel up F= 800 x 0.9 = 720

800g + 720 = 8560

15000-8560 =6440N

6440/80g = 8.21 hence I got 8

Reply 44

JasonH27

Original post by upthegunners

how did you even do 5ii)?

They specified the final speed of B, but didn't give the final direction of motion of B, meaning that you cannot just assume that the particle was travelling to the right, giving a positive speed, but as direction was not given, this means that the particle could have also been travelling 1.5m/s to the left, which in these style of questions, is actually a speed of -1.5m/s. So, in order to do the question, you had to apply the conservation of momentum to both 1.5 and -1.5 and they gave 4kg and 12kg respectfully :smile:

Reply 45

patterson

did anyone get K as 1/16 - C1 EXAM

(edited 10 years ago)

Reply 46

TheSilentFez

Original post by JasonH27

I can't believe I did this, but instead of dividing 18 by 1.5 and 4.5 to give 12kg and 4kg, I divided 28 by 1.5 and 4.5. I must have copied down the mass wrong and got 20 instead of 10! No!! How could I have done this!?
Anyway, aside from this sheer stupidity, my method was correct. How many marks do you think I will lose? 2,3, or 4? I'm hoping it's only 3 and not more.

Reply 47

Chriispy

Original post by patterson

did anyone get K as 1/16 - C1 EXAM

Ccea C1 isn't until 24th may?

Reply 48

jashfield730

Original post by Chriispy

Accel up F= 800 x 0.9 = 720

800g + 720 = 8560

15000-8560 =6440N

6440/80g = 8.21 hence I got 8

Heres how I did it look at the attached file

M1.pdf95.0KB

Reply 49

GingerCodeMan

Original post by jashfield730

Heres how I did it look at the attached file

I had a quick look at that, but I got 7 as well :smile:

and I rounded down from 7.5 or something like that.

Also, when you substitute N as 7, the Tension is approx. 14700 and when it's 8, tension is approx. 15200, so that makes me think that 7 must be correct.

Reply 50

505351

The test was alright apart from Q7. I'll probably get a high B now even though I wanted that A.
For the lift i got 7 and a lot of people in my year got 7.

Reply 51

patterson

Original post by Chriispy

Ccea C1 isn't until 24th may?

edexcel

Reply 52

ririlarov

I don't understand how people are getting 10.5 for Q for q1 :s-smilie:

defs 11.2

Reply 53

jashfield730

Original post by patterson

edexcel

Just so you know ccea has got nothing to do with edexcel

ccea is the Northern Ireland exam board
edexcel is an england based board(mainly)

(edited 10 years ago)

Reply 54

ririlarov

OMG I am the biggest idiot ever, cryyyyyyyyyyyyyy. I did 10 sin70 instead of 10sin60 fmlllllllll

Reply 55

ririlarov

and I did 10cos 60, just when I was copying out the 70 degree angle was so close aaaaaaaaaaahhh. feck sake, i've lost enough marks through lack of understanding i dont need to lose more through stupidity wehhh

Reply 56

ririlarov

Here is my working for 1 :smile:

P = 5.32N and Q = 10.5N
Too bad I got Q to equal 11.2N on the actual exam, fsfs

Reply 57

Liquid_Matterz

I found the exam was brilliant until question 5 (ii) and onwards. Eventually got part 6 but I doubt the examiner will be able to read my last minute scribble. I feel that question 7 was so difficult due to CCEA's awful wording. I interpreted "Tom exerts a force P newtons, at right angles to the pole, at C and a force Q newtons at D", meaning Q and P were both right angles until part 3. Anyone else have the same problem?

Reply 58

TheSilentFez

Original post by jashfield730

Heres how I did it look at the attached file

I did the same in that I took the Normal Reaction of the people in the lift as the downwards. Unfortunately, I forgot that I was considering forces acting on the lift only so I did the equation:
15,000-7840-856x=0.9(800+80x) where x is the number of people.
Basically, I made the equation equal to mass of both the lift and all the people times the acceleration. 3 or more marks just tossed in the bin...wonderful.
Combined with the stupid marks lost in the momentum question, I'm not very happy.

Alternatively, there is a much easier way:
F=ma
15000-800g-80g=0.9(800+80x)
which gives the same answer of 7.5something.

(edited 10 years ago)

Reply 59

ririlarov