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Mr M's OCR (not OCR MEI) Core 1 Answers May 2013

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Original post by Wowzerss
MR M, what was question 7ii and how did you go about it? If I can remember correctly I found the min point using dy/dx and then just said x<min point (cannot remember co-ordinate).

I appreciate you putting up these answers :smile:


Posted from TSR Mobile


7ii) Solve (2x4)(x3)12(2x-4)(x-3) \leq 12

Expand the brackets and simplify (make one side of the inequality zero). Sketch the quadratic inequality and state the answer.
Reply 101
for quadratic graph had intersection of (1.5,0) (-2,0) instead of (-1.5,0) (2,0)

How many marks lost?
Original post by TW2112
Mr. M, if I did all the correct workings for 10i but got k = 4, then did all the correct workings for 10iii but then got the wrong coordinates, how many marks would I lose? Would I get all the marks for ECF, or if not, how many would I lose?


Lose 1 for 10i) and 1 or 2 at the end.
Reply 103
On the last question I got (1,0) and I put it in and it worked I don't know where I went wrong :/
Original post by bardsleyp
Can someone please explain this to me (ii) (5 marks) , I think I got that and then changed it to x>0 or x<5 , how many marks will I lose?


Lose 1.
Original post by Dugald
could you maybe take a photo of the paper and post it?


It's copyright. I can't do that.
Reply 106
Original post by Mr M
Lose 1.


For the decreasing function question, I accidentally did dy/dx = 4x+1
So I got x < -1/4
How many marks will I drop?
For question 6ii where you have to find B (-2,-10), I know the correct method to find it is via considering the centre of the circle (M) as the mid point and working from that (A + B)/2 = M.
But how many marks would I lose (if any) for solving it by considering they are directly opposite in a straight line and they are an equal distance from M so getting from A to M is the same as going from M to B so adding that difference to M. i.e. (2,2) to (0,-4) is going -2 in x and -6 in y therefore A is at (0-2,-4-6) = (-2,-10). Will this lose me a working mark, in your opinion?

Thanks for the answers btw
Original post by Dugald
what was 6ii and 9iii I forgot the questions


6ii) The point A (2, 2) lies on the circumference of C. AB is a diameter, find B.

9iii) y=4 meets the curve y=2x^2-x-6 at P and Q. Find PQ.
Reply 109
how do you do question 6ii, I forgot what the question was
Reply 110
Original post by Mr M
Mr M's OCR (not OCR MEI) Core 1 Answers May 2013


1. (i) 12512 \sqrt 5 (2 marks)

(ii) 454 \sqrt 5 (1 mark)

(iii) 555 \sqrt 5 (1 mark)


2. x=12x=\frac{1}{2} or x=1x=-1 (5 marks)


3. (i) f(x)=212x3f'(x)=2-\frac{12}{x^3} (3 marks)

(ii) f(x)=36x4f''(x)=\frac{36}{x^4} (2 marks)


4. (i) 3(x+32)2+1343(x+\frac{3}{2})^2+\frac{13}{4} (3 marks)

(ii) (32,134)(-\frac{3}{2}, \frac{13}{4}) (3 marks)

(iii) 39-39 (2 marks)


5. (i) Correct sketch (2 marks)

(ii) y=2(x+5)2y=\frac{2}{(x+5)^2} (2 marks)

(iii) Stretch scale factor 12\frac{1}{2} parallel to y axis (2 marks)


6. (i) Centre (0,4)(0, -4) and radius 2102 \sqrt{10} (3 marks)

(ii) (2,10)(-2, -10) (2 marks)


7. (i) x<18x<-\frac{1}{8} (2 marks)

(ii) 0x50 \leq x \leq 5 (5 marks)


8. 6x+2y1=06x+2y-1=0 (7 marks)


9. (i) Correct sketch with intersections at (-1.5, 0) and (2, 0) and (0, -6) (5 marks)

(ii) x14x \leq \frac{1}{4} OR x<14x < \frac{1}{4} (either will be marked correct) (3 marks)

(iii) 4.54.5 (4 marks)


10. (i) k=5k=-5 (7 marks)

(ii) Minimum (2 marks)

(iii) (2,27)(-2, -27) (5 marks)


I'll be around to answer questions shortly.


Mr M, For question 9iii, not too sure what I did but I ended up with co-ordinates (1/4 , 4) any idea how many marks I'll lose?

HELP PLEAAAASEE :frown:


Posted from TSR Mobile
Original post by daisyrchds
any suggestions on why for the last part of question 10 i got (1,0)?! I differentiated the equation given then equated it to 9 assuming they would have the same gradient, as y=9x-9 was the tangent to the curve. lots of questions, sorry!


Your method is ok.
Original post by Mr M
Mr M's OCR (not OCR MEI) Core 1 Answers May 2013


1. (i) 12512 \sqrt 5 (2 marks)

(ii) 454 \sqrt 5 (1 mark)

(iii) 555 \sqrt 5 (1 mark)


2. x=12x=\frac{1}{2} or x=1x=-1 (5 marks)


3. (i) f(x)=212x3f'(x)=2-\frac{12}{x^3} (3 marks)

(ii) f(x)=36x4f''(x)=\frac{36}{x^4} (2 marks)


4. (i) 3(x+32)2+1343(x+\frac{3}{2})^2+\frac{13}{4} (3 marks)

(ii) (32,134)(-\frac{3}{2}, \frac{13}{4}) (3 marks)

(iii) 39-39 (2 marks)


5. (i) Correct sketch (2 marks)

(ii) y=2(x+5)2y=\frac{2}{(x+5)^2} (2 marks)

(iii) Stretch scale factor 12\frac{1}{2} parallel to y axis (2 marks)


6. (i) Centre (0,4)(0, -4) and radius 2102 \sqrt{10} (3 marks)

(ii) (2,10)(-2, -10) (2 marks)


7. (i) x<18x<-\frac{1}{8} (2 marks)

(ii) 0x50 \leq x \leq 5 (5 marks)


8. 6x+2y1=06x+2y-1=0 (7 marks)


9. (i) Correct sketch with intersections at (-1.5, 0) and (2, 0) and (0, -6) (5 marks)

(ii) x14x \leq \frac{1}{4} OR x<14x < \frac{1}{4} (either will be marked correct) (3 marks)

(iii) 4.54.5 (4 marks)


10. (i) k=5k=-5 (7 marks)

(ii) Minimum (2 marks)

(iii) (2,27)(-2, -27) (5 marks)


I'll be around to answer questions shortly.


sorry, for question 5)i) what was the correct sketch
For the very last part, i correctly calculated x=0 and x=-2, showing all my working. I then had no idea, so I then guessed and put x=-2 y=-27 underneath. I wrote that down but didn't put any working and didn't obviously exclude x=0. Will I get all the marks?
Thanks for the answers!
MR MMMMMMMM!!!!!!

You know you said you couldn't put up the paper but you could tell us what the question was - well, what was the full last question? Just cause I want another stab at it!

Thanks!!! :smile:

Fruity x
Reply 115
Original post by Mr M
Your method is ok.


For the decreasing function question, I accidentally did dy/dx = 4x+1
So I got x < -1/4
How many marks will I drop?
Original post by Smiteh
Does anyone roughly remember the questions for 4iii and 7i, I'm not exactly sure what answer i put and i feel it may help jog my memory with the question, other than these I feel i maxed the paper :smile: yey


4iii) Calculate the discriminant of 3x^2 + 9x + 10

7i) Solve 3 - 8x > 4
Original post by James_01
for the question on the radius and center of a circle i got the center correct but for the radius i put
(24-16)^1/2 instead of (24+16)^1/2 and hence ended up with 8^1/2 as my radius. I was wondering how many marks i will drop out of 3? Also i got all the other questions right but i really need to get 100 ums on this pape,r does dropping 1 or 2 marks now mean i cant get 100?


Drop 1. No-one NEEDS 100 UMS - it isn't that important.
Original post by Mr M
7ii) Solve (2x4)(x3)12(2x-4)(x-3) \leq 12

Expand the brackets and simplify (make one side of the inequality zero). Sketch the quadratic inequality and state the answer.


If we got the correct inequality but didn't draw the sketch?

And if, for the transformation question, we wrote down y=2/((x+5)^2) and then expanded it? Any marks lost either way?
Reply 119
Hi,

(New to TSR) Been put through this AS a year early :/ and by checking the mark sheme, it looks like ive scored about 50/72.

I was hoping for an A but doubt the boudaries will be that low! Anyone got a good guess what it might equate to??

Thanks

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