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Mr M's OCR (not OCR MEI) Core 1 Answers May 2013

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Original post by Z.M.1
For q4 I simplified it to 3 1/4 instead of 13/4 would I lose any marks? And for q5 if I read the question wrong, and moved the graph 4 in negative x and got 2/(x+4)^2 how many marks would I lose?

Also is the correct sketch for the _)|(_ something like that? Again q5
As the grade boundaries haven't changed since june12 61/72 for a and 54/72 for , what would you expect?


Thank you!


Q4) that's fine

Q5) lose 1 mark

I've provided a link to the correct graph on wolfram alpha a few pages ago.

No idea about grade boundaries.
I'm busy again for another hour or so folks. Back later.
Reply 262
Hi Mr m for question 7ii.
i left it has x<(equal to)5
also for Q8) I divided by 2
how many marks would i drop?
Thanks
(edited 10 years ago)
Original post by Mr M
Mr M's OCR (not OCR MEI) Core 1 Answers May 2013


1. (i) 12512 \sqrt 5 (2 marks)

(ii) 454 \sqrt 5 (1 mark)

(iii) 555 \sqrt 5 (1 mark)


2. x=12x=\frac{1}{2} or x=1x=-1 (5 marks)


3. (i) f(x)=212x3f'(x)=2-\frac{12}{x^3} (3 marks)

(ii) f(x)=36x4f''(x)=\frac{36}{x^4} (2 marks)


4. (i) 3(x+32)2+1343(x+\frac{3}{2})^2+\frac{13}{4} (3 marks)

(ii) (32,134)(-\frac{3}{2}, \frac{13}{4}) (3 marks)

(iii) 39-39 (2 marks)


5. (i) Correct sketch (2 marks)

(ii) y=2(x+5)2y=\frac{2}{(x+5)^2} (2 marks)

(iii) Stretch scale factor 12\frac{1}{2} parallel to y axis (2 marks)


6. (i) Centre (0,4)(0, -4) and radius 2102 \sqrt{10} (3 marks)

(ii) (2,10)(-2, -10) (2 marks)


7. (i) x<18x<-\frac{1}{8} (2 marks)

(ii) 0x50 \leq x \leq 5 (5 marks)


8. 6x+2y1=06x+2y-1=0 (7 marks)


9. (i) Correct sketch with intersections at (-1.5, 0) and (2, 0) and (0, -6) (5 marks)

(ii) x14x \leq \frac{1}{4} OR x<14x < \frac{1}{4} (either will be marked correct) (3 marks)

(iii) 4.54.5 (4 marks)


10. (i) k=5k=-5 (7 marks)

(ii) Minimum (2 marks)

(iii) (2,27)(-2, -27) (5 marks)


I'll be around to answer questions shortly.


sorry to keep pestering you as you have been an amazing help, but how did you work out number 8 as again got something slightly different. thanks again
Reply 264
Original post by aran0909
Hi Mr m for question 7ii.
i left it has x<(equal to)5
how many marks would i drop?
Thanks


I would imagine only one mark.
Reply 265
Original post by Majeue
I would imagine only one mark.

Thanks what about if i divided by 2 on Q8?
Mr M, for question 9 part ii) , I stated that the range of values was
-3/2 < x < 1/4 , I also go two solutions for the final question but had a line saying A = (-2,-27) as my final line of working (underlined). How many marks do you reckon I will lose?
Reply 267
Does anyone have all of the questions?
People keep on asking for individual ones so it might make sense to put them all up at once! :-)
Reply 268


How many marks would I get if I did the right curve but only in the first quadrant (i.e. I didn't put a second curve symmetrical to it on the opposite side of the y-axis)?
Reply 269
Original post by aran0909
Thanks what about if i divided by 2 on Q8?


If you just left it in the form 3x+y-1/2 = 0, that should only lose the final mark. You'll have to tell me what answer you got.
Reply 270
Original post by Rrobba
How many marks would I get if I did the right curve but only in the first quadrant (i.e. I didn't put a second curve symmetrical to it on the opposite side of the y-axis)?


You would get 1/2 marks.
Reply 271
Original post by fluker6696
Mr M, for question 9 part ii) , I stated that the range of values was
-3/2 < x < 1/4 , I also go two solutions for the final question but had a line saying A = (-2,-27) as my final line of working (underlined). How many marks do you reckon I will lose?


For 9ii, you might get 1, or 2 if you're lucky.
For the final, you should only lose 1 mark, or may get full marks.
Reply 272
Original post by Mr M
Mr M's OCR (not OCR MEI) Core 1 Answers May 2013


1. (i) 12512 \sqrt 5 (2 marks)

(ii) 454 \sqrt 5 (1 mark)

(iii) 555 \sqrt 5 (1 mark)


2. x=12x=\frac{1}{2} or x=1x=-1 (5 marks)


3. (i) f(x)=212x3f'(x)=2-\frac{12}{x^3} (3 marks)

(ii) f(x)=36x4f''(x)=\frac{36}{x^4} (2 marks)


4. (i) 3(x+32)2+1343(x+\frac{3}{2})^2+\frac{13}{4} (3 marks)

(ii) (32,134)(-\frac{3}{2}, \frac{13}{4}) (3 marks)

(iii) 39-39 (2 marks)


5. (i) Correct sketch (2 marks)

(ii) y=2(x+5)2y=\frac{2}{(x+5)^2} (2 marks)

(iii) Stretch scale factor 12\frac{1}{2} parallel to y axis (2 marks)


6. (i) Centre (0,4)(0, -4) and radius 2102 \sqrt{10} (3 marks)

(ii) (2,10)(-2, -10) (2 marks)


7. (i) x<18x<-\frac{1}{8} (2 marks)

(ii) 0x50 \leq x \leq 5 (5 marks)


8. 6x+2y1=06x+2y-1=0 (7 marks)


9. (i) Correct sketch with intersections at (-1.5, 0) and (2, 0) and (0, -6) (5 marks)

(ii) x14x \leq \frac{1}{4} OR x<14x < \frac{1}{4} (either will be marked correct) (3 marks)

(iii) 4.54.5 (4 marks)


10. (i) k=5k=-5 (7 marks)

(ii) Minimum (2 marks)

(iii) (2,27)(-2, -27) (5 marks)


I'll be around to answer questions shortly.


For K=-5 I worked it out to be -49 I did all the correct working but I put in a negative sign instead of a positive infront of K at one point. I multiplied out the brackets and found dy/dy made it equal to 0 and substituted -3 for x.

Then because this answer was wrong I couldn't do (-2,-27) I did the correct working but stopped when I couldn't find the multiples (because it didn't work) although I did do simultaneous equations and then showed an alternative method of dy/dx up until that point..

Is it possible to get any method marks and if so could you hazard a guess at how many marks I'll lose/get.. Thanks!! :smile: I got nearly full marks in the rest of the paper I'm just worried the wrong sign will cost me an A :frown:(((((
(edited 10 years ago)
Will I lose marks for not not writing the differentiation answers in a more suitable format? For example I wrote 36x^-4 instead of 36 over x^4 and the same with the other differentiation question.
Original post by aran0909
Hi Mr m for question 7ii.
i left it has x<(equal to)5
also for Q8) I divided by 2
how many marks would i drop?
Thanks


drop 2 marks and 1 mark respectively
Original post by hayhayhay1
sorry to keep pestering you as you have been an amazing help, but how did you work out number 8 as again got something slightly different. thanks again


I have provided the question earlier in the thread. Try working it out again?
Original post by fluker6696
Mr M, for question 9 part ii) , I stated that the range of values was
-3/2 < x < 1/4 , I also go two solutions for the final question but had a line saying A = (-2,-27) as my final line of working (underlined). How many marks do you reckon I will lose?


9ii) you might get 1 mark if you are lucky

full marks on the last part
Original post by Rrobba
How many marks would I get if I did the right curve but only in the first quadrant (i.e. I didn't put a second curve symmetrical to it on the opposite side of the y-axis)?


drop 1 mark
Original post by Whyllee
For K=-5 I worked it out to be -49 I did all the correct working but I put in a negative sign instead of a positive infront of K at one point. I multiplied out the brackets and found dy/dy made it equal to 0 and substituted -3 for x.

Then because this answer was wrong I couldn't do (-2,-27) I did the correct working but stopped when I couldn't find the multiples (because it didn't work) although I did do simultaneous equations and then showed an alternative method of dy/dx up until that point..

Is it possible to get any method marks and if so could you hazard a guess at how many marks I'll lose/get.. Thanks!! :smile: I got nearly full marks in the rest of the paper I'm just worried the wrong sign will cost me an A :frown:(((((


drop 1 mark in the first part and 2 marks at the end
Original post by Maths927384
Will I lose marks for not not writing the differentiation answers in a more suitable format? For example I wrote 36x^-4 instead of 36 over x^4 and the same with the other differentiation question.


That's fine.

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