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S1 help on discrete random variables!

I cant seem to do this question, can somebody give me a hand? I can't seem to do part e!

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Reply 1
Basically you find all the combinations of what X1 and X2 could be that satisfy the inequality (i.e. they have to be more than 1, but equal to 3 or less), then you add up the probabilites of the combinations occurring:

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(edited 10 years ago)
Reply 2
Original post by Piguy
Basically you find all the combinations of what X1 and X2 could be that satisfy the inequality (i.e. they have to be more than 1, but equal to 3 or less), then you add up the probabilites of the combinations occurring:

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I'm pretty sure there's no "inequality" as such for X1+X2X_1 + X_2, combinations like (3,2) and (1,3) etc should still be possible.
Reply 3
Original post by justinawe
I'm pretty sure there's no "inequality" as such for X1+X2X_1 + X_2, combinations like (3,2) and (1,3) etc should still be possible.


Woops, looking at f, silly me
Reply 4
In that case you just need to find the combinations of what X1 + X2 could be:

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