AQA Physics Unit 1 PHYA1 20th May 2013

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Apparently quite a few people for my school and a close school found this really difficult, maybe lower boundaries than people are saying?

A couple of people I know as well messed up a lot as well, but the generally everyone would agree that it's easier compared to past papers.

Reply 1281

Namige

Original post by .raiden.

Not necessarily, I got 112 with 64/70. So it seems as though 1 raw mark is just above 1 ums.

Sorry, I meant I got 63/70. Just checked on the aqa website - http://www.aqa.org.uk/exams-administration/about-results/uniform-mark-scale/convert-marks-to-ums

Reply 1282

StalkeR47

Mr Suhk.... Check your revision book and then talk. Do not just say what you think is correct.

Reply 1283

StalkeR47

HERE!!!!!! http://wiki.answers.com/Q/What_is_the_difference_between_hadrons_and_leptons

Reply 1284

Mr.Suhk

for which question mate, im pretty sure im right about the interactions

Reply 1285

Zakee

Original post by Abbseh

Apparently quite a few people for my school and a close school found this really difficult, maybe lower boundaries than people are saying?

It all depends on the country. What people must realize is because the people who usually comment here roughly A/B boundary, they're going to say 'oh the exam was easy/moderately easy/fine'. So the grade boundaries here may be augmented slightly. I remember last year during my GCSEs, people here were saying, exam was easy, so 90 UMS will be 54/60. Surprisingly, 50/60 was 90 UMS. It all does truly depend.

My personal belief is that this paper will be 67-68/70 for 120 UMS.

Reply 1286

StalkeR47

Original post by Mr.Suhk

for which question mate, im pretty sure im right about the interactions

http://wiki.answers.com/Q/What_is_the_difference_between_hadrons_and_leptons

Reply 1287

Mr.Suhk

of course that true- lleptons are not affected by the strong interaction- this doesnt mean that hadrons are not affected by the weak.

Reply 1288

ac3xx

Original post by Mr.Suhk

what are you on about- they can experience more than one interaction - the weak affects all, strong only if made up of quarks

Hadrons interact through the strong force, Leptons through the weak. Both interact through the Electromagnetic Force if charged. Hadrons decay through the weak interaction, they don't interact through it.

Reply 1289

StalkeR47

Original post by ac3xx

CORRECT!

Reply 1290

Mr.Suhk

yes the weak interactions affects all particles though, thats what i mean to say

Reply 1291

pilotluke1

6c i got 2.9A then the next part i got 1.3A then i got 4.4 ohms then for the next part i calculated all the power dissapated correctly but mines added to 50.7 so when i divided by the current i didnt get exactly 12. how many marks will i get out of 12??? sorry if this poorly worded

Reply 1292

Blayney

Original post by StalkeR47

CORRECT!

A decay is still an interaction I think, and even if it isnt, if it decays by weak then it still experiences the weak force. All particles experience the weak force.

Reply 1293

StalkeR47

Original post by Mr.Suhk

yes the weak interactions affects all particles though, thats what i mean to say

No, you said hadrons interact through both strong and weak interaction. Careful!

Reply 1294

StalkeR47

Original post by Blayney

A decay is still an interaction I think, and even if it isnt, if it decays by weak then it still experiences the weak force. All particles experience the weak force.

Yes! And of course hadrons do not interact through weak interaction.

Reply 1295

GeneralOJB

Original post by pilotluke1

Did you calculate the power transformed by the battery?

Reply 1296

Mr.Suhk

Omg my bad. In my exam i wrote affects. Im sorry for my miswording, pretty **** at english.

Reply 1297

Zakee

Original post by StalkeR47

No, you said hadrons interact through both strong and weak interaction. Careful!

What about a neutron-neutrino interaction where the W- boson causes the neutrino to change into an electron? Or a proton - antineutrino interaction where the W+ boson causes the antineutrino to form a postiron?

Reply 1298

Abbseh

Original post by NedStark

A couple of people I know as well messed up a lot as well, but the generally everyone would agree that it's easier compared to past papers.

Everyone I've talked to around hated it and thought it was horrible, very few thought it was good. Thankfully I thought it was good but the overall consensus (not including the student room which obviously would say it was okay) thought it was a bit horrible. Apparently there were tears :/

Reply 1299

ShutUpLegs

Original post by GeneralOJB

The frequency of the photons are all the same, it was monochromatic light. There's a max KE as the electrons nearest to the surface only require the work function (minimum energy) to be removed. The one's deepest in the metal will require more energy and have a lower KE.

The question asked what affect would decreasing the frequency so does that agree with what I wrote, I think that's what I was trying to say. If you imagine the threshold frequency of a metal was

6\times10^{14}

for example, at this frequency the photons would only have energy to remove the electrons nearest to the surface as the photons absorbed by electrons further in would only cause them to collide with other particles within the metal and lose their KE.

Increasing the frequency then to

7\times10^{14}

say, will mean that electrons further from the metal's surface will have energy sufficient to leave the metal so more electrons emitted when freq increased?

I looked at a quick interactive animation and increasing frequency meant higher photoelectric current.