AQA Physics Unit 1 PHYA1 20th May 2013

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Reply 1480

Qari

Original post by StalkeR47

Are you guys still talking about intensity and frequency?

Yeah

Reply 1481

123456789012

For the oscilloscope question I wrote that the time base should be adjusted so that the time was 4ms per division instead of 2ms per division. Is that right? If so, how many marks would I get?

Reply 1482

Qari

Anyone know for the conservation of energy if I've proved it but not wrote anything would I at least get 1 mark?

Reply 1483

Qari

Original post by 123456789012

For the oscilloscope question I wrote that the time base should be adjusted so that the time was 4ms per division instead of 2ms per division. Is that right? If so, how many marks would I get?

It was 1ms per div not 2. If you counted the squares 10ms was at the 10th square
So it should have been 1ms to 2ms or 2.5ms

Reply 1484

swagadon

i really dont know why im still here, im not really finding out if i got things right,im only finding out that i might have got them wrong and reading better answers then mine, this is depressing! hahahhaa

Reply 1485

Qari

Original post by swagadon

What questions were you worried about? Let's see if you got similar to mine :smile:

Reply 1486

amar96

Original post by Qari

It was 1ms per div not 2. If you counted the squares 10ms was at the 10th square
So it should have been 1ms to 2ms or 2.5ms

it wanted 2 waves in 10 squares so if at 1ms/div there was 1 wave.... *three dots in triangle* 2ms/div will give you 2 waves..think that KO

Reply 1487

benroxo

Original post by Qari

It was 1ms per div not 2. If you counted the squares 10ms was at the 10th square
So it should have been 1ms to 2ms or 2.5ms

it had to be at least 2ms per division to fit two waveforms on? each wavelength was 10ms and there was only 10 squares.

Reply 1488

123456789012

Original post by Qari

It was 1ms per div not 2. If you counted the squares 10ms was at the 10th square
So it should have been 1ms to 2ms or 2.5ms

Oh no! Would I get even a single mark though? Say if I got around 60 raw marks, how many UMS do you reckon that would be?

Reply 1489

Qari

Original post by amar96

it wanted 2 waves in 10 squares so if at 1ms there was 1 wave.... *three dots in triangle* 2ms/div will give you 2 waves..think that KO

Someone said it was 2ms and they did to 4ms and would they have been able to see the 2 waves completely?

Reply 1490

Qari

Original post by 123456789012

Oh no! Would I get even a single mark though? Say if I got around 60 raw marks, how many UMS do you reckon that would be?

here you are check,
http://www.aqa.org.uk/exams-administration/about-results/uniform-mark-scale/convert-marks-to-ums

Reply 1491

StalkeR47

aaaaammmmamamam yaun yaun yaun :boring:

I am really tired. damit, I needed to do more revision on sociology.

Reply 1492

Qari

Original post by StalkeR47

aaaaammmmamamam yaun yaun yaun :boring:

I am really tired. damit, I needed to do more revision on sociology.

Just realies my mate has that exam tomorrow

Reply 1493

dr.zoidberg

Original post by Qari

It was 1ms per div not 2. If you counted the squares 10ms was at the 10th square
So it should have been 1ms to 2ms or 2.5ms

it was 2ms per square because it wanted 2 cycles. each cycle was 10ms and therefore 2 cycles would be 20ms. and if we divide this by the number of horizontal squares (10) we get 2ms per square.

Reply 1494

StalkeR47

OMG STOP TALKING ABOUT this oscilloscope. you are making me fall asleep. you got what you got. you did what you could. and you cannot change it, can u? so shhhh and wait for the results day.

Reply 1495

Qari

Original post by dr.zoidberg

it was 2ms per square because it wanted 2 cycles. each cycle was 10ms and therefore 2 cycles would be 20ms. and if we divide this by the number of horizontal squares (10) we get 2ms per square.

I'm saying Figure 2 not what we had to change

Reply 1496

v1k2a3t4

I swear the question said that there were 8 vertical divisions :s-smilie:

. So if 1 complete cycle was 10ms, 2 complete cycles would be 20ms, 20/8= 2.5ms per division? :confused:

Reply 1497

GeneralOJB

Original post by v1k2a3t4

I swear the question said that there were 8 vertical divisions :s-smilie:

. So if 1 complete cycle was 10ms, 2 complete cycles would be 20ms, 20/8= 2.5ms per division? :confused:

Yes, but you are interested in the horizontal divisions for the time base, as the time base is on the horizontal axes.

Reply 1498

Semanresu

Original post by Kayakayakaya

question 4, about the frequency being reduced, surely this has no effect unless the frequency is below the threshold frequency?

I think that lowering the frequency would mean less photon energy, hence KEmax is less because hf=KEmax+work function (constant). So the electrons have a lower kinetic energy.