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Mega A Level Maths Thread MK II

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Original post by justinawe
du≠dxdu \not= dx

Which is what you did in your substitution.


Original post by joostan
Beat me to it. :tongue:

Thanks :wink:
Original post by reubenkinara
I see! :banghead::banghead::banghead::banghead::banghead:
So glad this isn't the exam now!


I highly doubt you'd get a question like that in the exam, anyway :tongue:
Reply 2282
Avatar for tigerz
tigerz
Original post by joostan
Well, that's how it goes :biggrin:
Let's see . . .
Got another problem for you.
If log⁡102=x\log_{10}2=x and log⁡103=y\log_{10}3=y
Express log⁡5(36)\log_5(36) in terms of x and y. :smile:


Right so:

\log_{5}36=\frac{\log_{10}36}{\log_{10}5}

log⁡1036=log⁡104+log⁡109=log⁡1022+log⁡1032=2log⁡102+2log⁡103=2x+2y \log_{10}36={\log_{10}4}+{\log_{10}9}={\log_{10}2^2}+{\log_{10}3^2}=2{\log_{10}2}+2{\log_{10}3}=2x+2y

log⁡105=log⁡1010−log⁡102=1−x \log_{10}5=\log_{10}10-\log_{10}2=1-x

Therefore *drumroll* (This better be right!) log⁡536=log⁡1036log⁡105=2x+2y1−x \log_{5}36=\frac{\log_{10}36}{\log_{10}5}=\frac{2x+2y}{1-x}
Original post by justinawe
I highly doubt you'd get a question like that in the exam, anyway :tongue:



Original post by reubenkinara
I see! :banghead::banghead::banghead::banghead::banghead:
So glad this isn't the exam now!

There were two previous parts in the book and a hence show that, but hey - who cares?
Original post by tigerz
Right so:

\log_{5}36=\frac{\log_{10}36}{\log_{10}5}


log⁡1036=log⁡104+log⁡109=log⁡1022+log⁡1032=2log⁡102+2log⁡103=2x+2y \log_{10}36={\log_{10}4}+{\log_{10}9}={\log_{10}2^2}+{\log_{10}3^2}=2{\log_{10}2}+2{\log_{10}3}=2x+2y

log⁡105=log⁡1010−log⁡102=1−x \log_{10}5=\log_{10}10-\log_{10}2=1-x

Therefore *drumroll* (This better be right!) log⁡536=log⁡1036log⁡105=2x+2y1−x \log_{5}36=\frac{\log_{10}36}{\log_{10}5}=\frac{2x+2y}{1-x}

Yep :congrats:
(edited 10 years ago)
Original post by justinawe
I highly doubt you'd get a question like that in the exam, anyway :tongue:

Perhaps not, however that mistake was worrying :sadnod::sadnod::sadnod::sadnod:
Reply 2285
Avatar for tigerz
tigerz
Original post by joostan
There were two previous parts in the book and a hence show that, but hey - who cares?


Yep :congrats:


WOOOPPP! I hope there's a question like this tomorrow now :^_^:
Original post by tigerz
WOOOPPP! I hope there's a question like this tomorrow now :^_^:


Lol, you'll be one of the few who'll be able to do it :smile:
Anyone doing c2 tomorrow edexcel? any major tips for someone who is most likely to fail?!
75/75 on M4 June 2008!
Reply 2289
Avatar for tigerz
tigerz
Original post by joostan
Lol, you'll be one of the few who'll be able to do it :smile:


Haha, TSR taught meh logs LOOL :h: Thank youuuu for teaching π\pi :smile:
Old but gold. :awesome:

Spoiler

Reply 2291
Avatar for tigerz
tigerz
Original post by dippers
Anyone doing c2 tomorrow edexcel? any major tips for someone who is most likely to fail?!


Meeee, I'm sure you won't fail, I suggest you get some past papers done!

here you gooo :h:
C2 Revision.pdf266.3KB
Original post by tigerz
Haha, TSR taught meh logs LOOL :h: Thank youuuu for teaching π\pi :smile:


Es de nada. :smile:
Anytime. :biggrin:
Original post by Felix Felicis
Old but gold. :awesome:

Spoiler



I might be underthinking this but...

Spoiler

Original post by DJMayes
I might be underthinking this but...

Spoiler


Notice the discreet commas, it's a sequence rather than a series :tongue: Each term in the sequence only has 1 ±12\pm 1^{2}
Original post by DJMayes
I might be underthinking this but...

Spoiler



We're looking at the sequence, not the series, as I understand it.

EDIT: Gah, this is what happens when you preview your posts before posting. You end up being the second poster to everything!
(edited 10 years ago)
Reply 2296
Avatar for tigerz
tigerz
Original post by joostan
Es de nada. :smile:
Anytime. :biggrin:


Haha :smile:
Original post by Felix Felicis
Notice the discreet commas, it's a sequence rather than a series :tongue: Each term in the sequence only has 1 ±12\pm 1^{2}


Ah, possibly should've read that. :lol:
Original post by Scientific Eye
We're looking at the sequence, not the series, as I understand it.

EDIT: Gah, this is what happens when you preview your posts before posting. You end up being the second poster to everything!


Post and edit ftw :tongue:
Reply 2299
Avatar for Xx4L3x
Xx4L3x
5
5cosθ − 2sinθ = 0,

prove tanx = 2.5

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