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Ocr mei statistics 1 exam thread (24/05/13)

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Reply 240
Avatar for juniorx
juniorx
2
for the second part of the question about the women and the man winning prizes, did anyone times something by 4 and add it to something ^4
(edited 10 years ago)
Original post by krishkmistry
What did everyone do for the first part on q2 - I used combinations and I'm not sure


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me too, I did (5C2 x 5C1)/10C3 and i got 5/12 as my answer:s-smilie:
Reply 242
Avatar for juniorx
juniorx
2
Original post by tumblrgirl
me too, I did (5C2 x 5C1)/10C3 and i got 5/12 as my answer:s-smilie:


same here
Reply 243
Avatar for Blobar
Blobar
15
Lol theres no simplifying that fraction.
Original post by tumblrgirl
me too, I did (5C2 x 5C1)/10C3 and i got 5/12 as my answer:s-smilie:


I got 5/12 too :biggrin:

Are we wrong?

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Reply 245
Avatar for Blobar
Blobar
15
Original post by tumblrgirl
me too, I did (5C2 x 5C1)/10C3 and i got 5/12 as my answer:s-smilie:


Either way is fine im sure.
Reply 246
Avatar for Mahinder
Mahinder
plz someone tell me wat question 2 ii was ....
Reply 247
Avatar for juniorx
juniorx
2
Original post by Blobar
Either way is fine im sure.


what did people get for the second part of this question?
Original post by Blobar
Did you guyes get like 14. something for SD and then just x by 0.9 in the second part to get the 2nd SD and not take away 15 unlike the mean.


Yes I did :biggrin:

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I got 5/12 first time round then for some reason i put 5/6 if i used the answer of 5/6 for the next part of the question would i still get the marks for it?
Reply 250
Avatar for Blobar
Blobar
15
Original post by juniorx
what did people get for the second part of this question?


What was it?
Reply 251
Avatar for Blobar
Blobar
15
What I did was for part 2 is (5/12)^4 + (5/12)^3.

Dunno if thats right.
Reply 252
Avatar for juniorx
juniorx
2
Original post by Blobar
What I did was for part 2 is (5/12)^4 + (5/12)^3.

Dunno if thats right.

i did (5/12)^4 + 4(5/12)^3 x 7/12
Reply 253
Avatar for Blobar
Blobar
15
why the 7/12? and why the 4 x 5/12^3
Reply 254
Avatar for Mahinder
Mahinder
ok there was 23 data in total for the media and iqr question
I did 23 + 1 divdie by 2 which gave me the 12th value.
23x3/4 which gave me 17.25 rounding gives me the 18th turn
23/4 gives 5.75 rounding gives 6th turn. then just find the 18th number for q3 and 6th number for q1 to get iqr i did q3-q1
Reply 255
Avatar for Blobar
Blobar
15
Ah I see where you're coming from, yeah I probably did that wrong tbh.
Reply 256
Avatar for Blobar
Blobar
15
Prettty sure there was 25 numbers in the data set.
Reply 257
Avatar for Mahinder
Mahinder
and for cumlative graph it was a total of 200

to get median 200/2 = 100 using the graph 100 = 3.5
q1 was 50
q3 was 150
iqr = 100

using grpah 100 =3.5
so u should of got the same median and iqr r the same
Original post by x-Sophie-x
I got 5/12 too :biggrin:

Are we wrong?

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I also got that, I don't know what else it could have been.
Reply 259
Avatar for juniorx
juniorx
2
Original post by Blobar
why the 7/12? and why the 4 x 5/12^3


This is hard to explain so bear with me. i calculated the probability of getting the combination of part 1 3 times and the 4th probability is not 2 women and man not getting the prizes. Then i think there are 4 ways of arranging it and added this to the proability of the prizes being awarded 4 times. I did this because i think it asked for the probability of more or equal to 3 and it said there were 4 events

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