Can someone pleeeeeeeeeease explain to me how to identify structural Isomers from Mass Spectrometry, Like how do you know which fragment peaks to take and than what do you do with them.
I will seriously love you forever if someone does thankyouuuu
Can someone pleeeeeeeeeease explain to me how to identify structural Isomers from Mass Spectrometry, Like how do you know which fragment peaks to take and than what do you do with them.
I will seriously love you forever if someone does thankyouuuu
The peaks show you ions, for example a peak at 29 would be CH3CH2+. There may then be another peak at 43 which would be CH3CH2CH2+. There's no calculation to find out what it is you just have to guess by adding different masses. However they usually use 15 (CH3+) , 29 and 43 for a hydrocarbon. The very last peak shows the mr of the whole thing, however if there is a tiny tiny peak after it, ignore the tiny peak. Refer to this image for help about this
In the screenshot the m+ peak would be the mr of the final product.
So for example a m+ peak at 58 would be CH3CH2CH2CH3 which is butane.
Say you know the molecular formula of a compound and get given the mass spectrum of it, and the is a fragmentation peak, would it just be a case of trial and error to work it out?
The peaks show you ions, for example a peak at 29 would be CH3CH2+. There may then be another peak at 43 which would be CH3CH2CH2+. There's no calculation to find out what it is you just have to guess by adding different masses. However they usually use 15 (CH3+) , 29 and 43 for a hydrocarbon. The very last peak shows the mr of the whole thing, however if there is a tiny tiny peak after it, ignore the tiny peak. Refer to this image for help about this
In the screenshot the m+ peak would be the mr of the final product.
So for example a m+ peak at 58 would be CH3CH2CH2CH3 which is butane.
Ahhh Thank you
But how would you identify an isomer from the ion peaks? Like this question how do you know from the m/z 29 value, the isomer is butane and not 2methylpropane.
an someone explain why only two isomers can be formed in Question 4B(iii) - i do not get why only two isomers and not more ? thank you. It the june 2010 paper
i did in january. it was the worst ever score i have gotten in an exam.horrendus. did u do it?
nope I did f324 in january, we did the january paper for f325 as a mock in class. Hoping this junes paper should be a lot better considering how bad januarys was
But how would you identify an isomer from the ion peaks? Like this question how do you know from the m/z 29 value, the isomer is butane and not 2methylpropane.
If it was 2 methyl propane you wouldn't get peaks at 15, 29 and 43. It would be CH3CHCH3CH3 ( 2 methyl propane ) which does not support the absorption's.
For example you may get CH3CHCH2+ which is 42, which is not one of the peaks.
you just have to break it down and look at the individual ions as to what it could be.