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Original post by yodawg321
For the flame question on why it was a yellow or blue flame

I put its because there's a supply of oxygen so it's an complete combustion so gas is being produced (Co2)

For people who put incomplete combustion I don't understand how because Incomplete releases Carbon Monoxide and its a colourless gas :s


Incomplete combustion also produces carbon which burns yellow and is black not just carbon monoxide
Did anyone got S8 for the mass spec question?
Reply 2862
Original post by jacksonmeg
isnt it 240/24 = 10 moles, 2 moles = 134 or whatever it was, so 5x134= 1670


The 2 before N20 doesn't mean 2 moles, I think I just multiplied by 10.


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Reply 2863
One of the easiest papers i've done so far! grade boundaries should be high. What do you guys think!
Original post by Parrot654
what did people put for the way that the equilibrium shifted?
with temp
with pressure
with catalyst:smile:


Left left unchanged


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Original post by jacksonmeg
for the box question, ketone, ester, 2 different alkenes right ?


yepp thats what i got
Original post by Farringtonn
What did people do for the radical substitution?


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IBr -------> I + Br initiation
Br + Ch4 ---------> HBr + CH3 propagation
Ch3 + IBr -------> Br + Ch3I propagation

Ch3 + Br --------> Ch3br. Termination

Homolytic fission

Free radical substitution
Reply 2867
Original post by Zzzyax
i think i got 98/99 maybe 91 for an A



lol pipe down
Reply 2868
Original post by kingmango
I swear I got like +820 for the 24dm3 question? Anyone else get that? :frown:



Nah, it was 1640
Reply 2869
Original post by jacobfun
The 2 before N20 doesn't mean 2 moles, I think I just multiplied by 10.


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Nah you times it by 5
Original post by kingmango
I swear I got like +820 for the 24dm3 question? Anyone else get that? :frown:


No :frown:
i did 240/24=10 then something like 164/10 = 16.4 :s-smilie:
could you say radical substitution or did you have to say free radical
Reply 2872
Original post by FLLF
Nah, it was 1640


thats right, you times it by 5 not 10, the original one had 2 moles already.
Original post by yodawg321
Will they allow HCFs instead of HCFCs?


Maybe, they're called HFCs. I think they will let you off
Original post by jacksonmeg
for the box question, ketone, ester, 2 different alkenes right ?


Yep, thats right :smile:
Original post by Ray..
What did everyone write for the propagation
Steps + the one termination steps
From what I can remeber I did
CH4 + Br. -> CH3 + HBr
Ch3 + IBr ->> CH3I + Br.

Termination
CH3. + Br. --> CH3Br
That's right right ??


that's what I put :biggrin: There are quite a few termination steps for this reaction, you could have had
CH3. + Br. --> CH3Br
CH3. + I. --> CH3I
CH3. + CH3. --> C2H6
I. + I. --> I2
Br. + Br. --> Br2
I. + Br. --> IBr
as long as two radicals came together to form one product that is not a radical it's a termination step i think
Original post by FLLF
Nah, it was 1640

It was 820... 1640 would be 20 moles
Extremely easy - grade boundaries are gonna be sky high.

90/100 for an A?
Please tell me people just drew an octagon on the second page? I felt like an idiot :tongue:
Reply 2879
Original post by FLLF
Were the functional groups alkene and ester?


I put that I'm pretty confident with ester but I wasn't sure about alkene

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