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Reply 880
Yesssssss
Reply 881
that's what I got:smile:what were the states?
That exam was an absolute godsend for me! :biggrin:

I did screw up the 3 marker calculation with the volume of gas equation though. Checked through my paper about 10 times and then only realised at the end, and ran out of time before I could finish it :/ ah well!
Reply 883
that's what I gotwhat were the states?
Original post by Davelittle
the double bond number has to be the lowest, not the methyl groups :redface:

:colonhash: WHY WAS I NOT INFORMED OF THIS EARLIER? :angry:



Thanks btw :tongue:
Original post by King Hotpie
:colonhash: WHY WAS I NOT INFORMED OF THIS EARLIER? :angry:



Thanks btw :tongue:


Sorry :redface:

It was only 1 mark :smile:
I HATED the exam!!!!
I feel like so bad :frown:
But and least it's holidays
Original post by Jooost
tbh I found the entire first question hardest and I lost most of my marks there :c


Same!! :eek:
Original post by super121
I'm not complaining! :tongue:


Posted from TSR Mobile


Aha true, but F335 is so daunting :/

Original post by steviep14
and in terms of types


electrophilic addition

then

elimination?

also... was the half equation
2Cl- --> Cl2 + 2e-


Yup got all of that as well!



Likewise bro. I will dance like a mad man when it's all over! :tongue:
Original post by Jooost
that's what I got:smile:what were the states?


Which one?

2Cl-(aq)->Cl2(g)+e-

And

Na(g)->Na+(g)+e-
For the curly arrow one, I also drew an arrow from the F-H bond to the F, as well as from the C-Cl bond to the Cl and the F to the C. Was this wrong of me? I thought it also produced a positive hydrogen ion which would later go on to react with the hydrogen chloride?
The colour change one confused me...
There was no colour change right... as you can't oxidise a tertiary alcohol? D:
Original post by steviep14
The colour change one confused me...
There was no colour change right... as you can't oxidise a tertiary alcohol? D:


It stayed orange yes
Reply 893
Original post by steviep14
The colour change one confused me...
There was no colour change right... as you can't oxidise a tertiary alcohol? D:


Yea, they weren't gonna catch me out there! :tongue:


Posted from TSR Mobile
Original post by King Hotpie
I believe if you draw out 2,6- dimethyloct-5-ene it's exactly the same- are there any specific naming rules for this, or are they both allowed? How many marks was it, in case they aren't :colone:

yay that's what I got :biggrin: it was 2 marks
Reply 895
Original post by steviep14
The colour change one confused me...
There was no colour change right... as you can't oxidise a tertiary alcohol? D:


I think that that's the answer. xD It's what I put.
Original post by Davelittle
the double bond number has to be the lowest, not the methyl groups :redface:


no your incorrect numbering of methy groups takes priority
Original post by King Hotpie
For the curly arrow one, I also drew an arrow from the F-H bond to the F, as well as from the C-Cl bond to the Cl and the F to the C. Was this wrong of me? I thought it also produced a positive hydrogen ion which would later go on to react with the hydrogen chloride?


Curly arrows from partially negative F to partially positive C then curly arrow from C-Cl bond to partially negative Cl :smile:
Reply 898
Original post by Davelittle
the double bond number has to be the lowest, not the methyl groups :redface:


Pretty sure you won't get penalised for having the methyl groups with the lower number.
Original post by steviep14
The colour change one confused me...
There was no colour change right... as you can't oxidise a tertiary alcohol? D:

I thought that! I made sure I put the potassium dichromate was orange, to make sure I got at least one mark if I was wrong! I think all you had to do was put "no change as tertiary alcohols do not readily oxidise" for both marks though.

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