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OCR Chemistry F322~ 4th June 2013~ AS Chemistry

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oh no i think i've already lost 10 marks :frown:
Reply 3161
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zangorou
Lovely paper.. Apart from the 250dm3 enthalpy change one. I put 1630 (ish), what did everyone else get?
Reply 3162
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bliam
Original post by TheFootyKing19
2 marks for saying how ozone is maintained I stratosphere:
- O2 + O <----> O3 or can say reversible reaction
- rate of formation of ozone equals = rate of decomposition of ozone

Give propagation steps of NO
- NO + O3 --> NO2 + O2
- NO2 + O ---> NO + O2

How fermentation made:
Equation:
- glucose --> 2C2H5OH + 2CO2
Conditions:
- yeast enzyme or zymase at 37 degrees
- anaerobic



Ahh, I messed up on the fermentation equation but I believe that I got the other things in that question correct?
Original post by tiduswakka1
THIS IS WRONG! The empirical formula was C4H8O, but the molecular formula was C8H16O2 so it was an ester


No

The molecular number given was 72

Empirical formuula was c4h80 which has mr of 72

72/72 = 1 so the moevular formula was the same

C=o was resent but o-h was not

So it's either ketone or aldehyde
Original post by ClarkyC...
What did people get for the yield question and what were the values because some people got 95%ish and others did like 9000.../11000.. (Approx) and got like 82%


Answer is definitely 95.45% to 4 significant figures
Reply 3165
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Saif95
12
The space for the five marker where you had to identify the two structures was very small, I had to squeeze the answers in...:mad:
Reply 3166
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Zakee
Original post by Dizzie31
how was that the molecular formula? c4h8o is 72..
how'd you just put an O on it :?



I got the empirical formula as C4H8O, and the Molecular as C4H8O.
Original post by theCreator
YOU'RE WRONG. The actual molecule was C4H8O therefore it was either butanal or butanone.


The mr was 72, it had to be C4H8O, I'm not sure why they're questioning you...
Original post by tiduswakka1
THIS IS WRONG! The empirical formula was C4H8O, but the molecular formula was C8H16O2 so it was an ester


Using the molar ratio and empirical formula

the Mr of the empirical formula = 72
mr of compound = 72
72/72 = 1

so it was the same as the empirical formula which is C4H8O
Original post by Beanjamin
I think I got -4596


Oh no i got 4596 first then i changed it :s-smilie:
Original post by ClarkyC...
What did people get for the yield question and what were the values because some people got 95%ish and others did like 9000.../11000.. (Approx) and got like 82%


i got around 82% aswell
did anyone else get an aldehyde and a ketone with a Molecular formula of C4H8O for the infrared spectroscopy question?
Reply 3172
Avatar for Saif95
Saif95
12
Anyone has the paper??
Original post by jackitsme
you all are acting like its not normal to be around low 70's to be an A,has been many times pricks


Who are you calling a prick lmao, I was being friendly - hence the smiley face...
Reply 3174
Avatar for bliam
bliam
Original post by theCreator
YOU'RE WRONG. The actual molecule was C4H8O therefore it was either butanal or butanone.


I didnt write what it was called, I said what functional group it would have and drew the structure? Marks?
Original post by kingmango
How many marks is that worth?


only 2
Reply 3176
Avatar for bliam
bliam
Original post by the A* guy
did anyone else get an aldehyde and a ketone with a Molecular formula of C4H8O for the infrared spectroscopy question?


I did! But I only drew them out :/
Original post by Saif95
The space for the five marker where you had to identify the two structures was very small, I had to squeeze the answers in...:mad:


I had to use the entire page of "additional answer space"!


This was posted from The Student Room's iPhone/iPad App
Original post by bliam
I didnt write what it was called, I said what functional group it would have and drew the structure? Marks?


you prob only lost 1!
Original post by the A* guy
did anyone else get an aldehyde and a ketone with a Molecular formula of C4H8O for the infrared spectroscopy question?


I got a ketone and aldehyde :smile:

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