Do you mean out of phase or 180 degrees out of phase? out of phase can be anything that is not in phase with a point, wheres a point in anti phase must be 180 degrees out of phase.
Yes, If blue light goes from air into water its frequency will remain constant but its speed will decrease and so will its wavelength as when you draw diagrams the waves get closer together.
I wouldn't worry why shorter wavelengths refract more, just know that shorter wavelengths refract greater than larger wavelengths and therefore blue refracts more than red. So when you draw a diagram with a red and blue ray, the blue ray must refract closer to the normal.
One time period is between adjacent compressions. If the wave had traveled T the positions would basically look the same, the particles would have just moved up the line. However as 3/4T has passed then the compressions must be 3/4 along the line between two compressions.
If that does not make sense I will try to explain further.
Hi, is there any chance you could explain further, the bits that I don't understand is, if one wavelength (distance from 2 adjacent compressions ) is the time period as the time period = the amount of time taken for one complete oscillation, then how do we know where the particles would be at t +3/4T, I find it really confusing? Thanks
If you draw a diagram of a sine wave and label the axis 0, pi/2, pi, 3pi/2 and 2pi
Take the point 0, the point in phase with that is 2pi as it is a full wavelength ahead. Waves that are in phase are whole number of wavelengths ahead.
However the point at pi is not in phase with 0 as it is half a wavelength ahead, therefore it is out of phase. And because it is half a wavelength ahead this means it is in antiphase. Whenever two points are half a wavelength apart they are in antiphase.
Hi, is there any chance you could explain further, the bits that I don't understand is, if one wavelength (distance from 2 adjacent compressions ) is the time period as the time period = the amount of time taken for one complete oscillation, then how do we know where the particles would be at t +3/4T, I find it really confusing? Thanks
The wave travels at a constant speed. So if we take the first compression, in one time period that compression will be in the same position as the second compression. As it travels at a constant speed if half a time period had passed then the first compression must now be half way between its original position and the original position of the second position.
If a tenth of a time period had passed then it would have been a tenth of the way along. Therefore if 3/4T has passed it must be three quarters between the original compression's.
If you draw a diagram of a sine wave and label the axis 0, pi/2, pi, 3pi/2 and 2pi
Take the point 0, the point in phase with that is 2pi as it is a full wavelength ahead. Waves that are in phase are whole number of wavelengths ahead.
However the point at pi is not in phase with 0 as it is half a wavelength ahead, therefore it is out of phase. And because it is half a wavelength ahead this means it is in antiphase. Whenever two points are half a wavelength apart they are in antiphase.
Thank youuuus , how is internal resistance measured?
If you draw a diagram of a sine wave and label the axis 0, pi/2, pi, 3pi/2 and 2pi
Take the point 0, the point in phase with that is 2pi as it is a full wavelength ahead. Waves that are in phase are whole number of wavelengths ahead.
However the point at pi is not in phase with 0 as it is half a wavelength ahead, therefore it is out of phase. And because it is half a wavelength ahead this means it is in antiphase. Whenever two points are half a wavelength apart they are in antiphase.
That makes sense. Sorry to bother you again, but please if you get a chance can you help me on Jan 2009 qu 13 b?
If we take a solar cell as an example. Have the solar cell in series with an ammeter and a variable resistor. Have a voltmeter in parallel with the solar cell. Vary the resistance and record current and voltage.
as V = E - Ir rearrange to form V = -rI + E it is in the form y=mx+c V on y axis I on x axis therefore E will be y intercept so internal resistance, r will be the gradient.
That makes sense. Sorry to bother you again, but please if you get a chance can you help me on Jan 2009 qu 13 b?
Current is split, if 30mA goes in then the current in both wires must = 30mA. 20mA in one wire so 10mA in the other wire so I1 = 10mA 15mA leave the first wire so 5mA must be remaining therefor I2 is 5mA as current is conserved and 30mA went in, 30mA must also leave therefore I3 must be 30mA.
If we take a solar cell as an example. Have the solar cell in series with an ammeter and a variable resistor. Have a voltmeter in parallel with the solar cell. Vary the resistance and record current and voltage.
as V = E - Ir rearrange to form V = -rI + E it is in the form y=mx+c V on y axis I on x axis therefore E will be y intercept so internal resistance, r will be the gradient.
Thank you XD, what other experiments other than resistivity do we need to be able to understand and apply?
Can someone please tell me the equation to calculate path difference from phase difference? And the equations derived from the doppler effect, asap would be awesome