Do we need to know the proof of diffraction grating?
My teacher said that it was in the specification, so we should know it, but it hasn't come up before, and I don't know it (so hopefully it won't come up)
Basically it was the Jan 13' one, the answers essentially asking for the path difference of the first order. I'm a bit rusty, since January to be fair!
haha no worries bro, its good we had this discussion, it actually made me think and be sure hope you get it now though p.s. you look like a 120 UMS boy you know your info my man, its just abit of confusion we all get so dw
Oh thank you very much! You are also 120UMS boy. You will do really really well as I can already see.
Oh thank you very much! You are also 120UMS boy. You will do really really well as I can already see.
i really hope so man, would help put off so much pressure for my phya4 exam. btw are all you lot willing to talk about this exam after tomorrow or are you gnna chicken out (maybe like me) lool.
How do you work out critical angle? And what's the definition of critical angle?
SinC=n2/n1 where n1>n2
The critical angle is the incident angle at which the refracted ray will travel across the boundary of the substances. Any more than the critical angle and total internal reflection will occur.
You're right, sorry I should have made myself clearer. The maxima do indeed contain all of the colours from white light (only in the case where white light is used), but they just pick up a red tinge the further away they get from the central maxima. Apologies for any confusion caused there.
However, do remember that each maxima will only contain all the colours of the spectrum if white light is used. If, for example, a laser light is used (red light), then all of the maxima will take on a red hue/tinge/colour.
yeah, this only happens for white light
for a red laser or any other monochromatic light source, you will only get the colour of that wavelength
hi, can anyone help me with question 6.(a) (ii) on the june 2012 paper. The mark scheme doesnt make sense to me?
as I understand it, any point within the same loop is basically the same in terms of their phase difference from another point on another loop
it does seem weird, because on that question, point X is clearly not at the max amplitude point (it is slightly to the right of it), so it doesn't seem to make sense that X and Y would be exactly out of phase by 180 degrees, because you'd think for this to be the case, point X would have be at the peak and point Y would have to be at the trough