Year 12s: what will be the first way you research your future options? >>

Year 12s: what will be the first way you research your future options? >>

Year 12s: what will be the first way you research your future options? >>

ocr a f325 revision thread

Scroll to see replies

Original post by A-New-Start

i told you the ans to that one, didn't i?

which thread was it?

Original post by DudeBoy

Same amount of energy, spread over a smaller volume, more atoms per volume, so more frequent collisions resulting in more successful collisions.

can you say exceeds Ea?

Who is ready for this??

Original post by AyshaK

Thanks you're a lifesaver haha good luck with your exam :smile:

:smile:

All the best of luck for today and thank you :smile:

:smile:

Original post by tom2013

Who is ready for this??

Me

Posted from TSR Mobile

Got a question for you guys (I know the answer its just to help with revision) What factors determine the pH of a buffer solution???

Original post by otrivine

can you say exceeds Ea?

Yeah

:smile:

Original post by beccac94

Got a question for you guys (I know the answer its just to help with revision) What factors determine the pH of a buffer solution???

The ratio of acid to salt of acid and the Ka value of the acid :smile:

:smile:

Original post by beccac94

Got a question for you guys (I know the answer its just to help with revision) What factors determine the pH of a buffer solution???

Ka

and

conc ratio of HA/A-

Original post by otrivine

All the best of luck for today and thank you :smile:

:smile:

good luck to you to :smile:

:smile:

Original post by chignesh10

Me

Posted from TSR Mobile

Full marks??

Original post by eggfriedrice

If I had an equation O3 + C2H4 -> 2HCO + 1/2 O2
initial rate = 1x10^-12

What would the rate of formation of O2 be?

Anyone?

Original post by DudeBoy

The ratio of acid to salt of acid and the Ka value of the acid :smile:

:smile:

Original post by A-New-Start

Ka

and

conc ratio of HA/A-

You can also have temperature for the answer as well :smile:

:smile:

Original post by eggfriedrice

Anyone?

1/4 of the intial rate

Original post by eggfriedrice

Anyone?

I think it would be four, because for every 4 moles of HCO there is one mole of O2.

(Like HCO is four times 02)

Original post by DudeBoy

1/4 of the intial rate

Why? And is that all you're given to work it out?

I dont see how sodium ethanoate is a salt of that. Anyone care to explain?

please can someone help me june 2010 paper q7b I get it all just not why you multiply the conc by 40 as well as 34? where's the 40 from?

Posted from TSR Mobile

(edited 10 years ago)

Original post by _HabibaH_

Why? And is that all you're given to work it out?

2 moles of HCHO = intial rate
In the same reaction 1/2O2 is formed
So for every one mol of HCHO formed 1/4 moles of O2 is formed
Do you get it? :smile:

:smile:

not specimen paper, jan 2010!

I mean June :tongue:

:tongue:

Posted from TSR Mobile

Quick Reply

Related discussions

Latest

Trending

Trending

Articles for you

Students react after A-level Geography Paper 1 on 17 May 2023

Students react after A-level Geography Paper 1 on 17 May 2023

Students react after A-level Biology Paper 1 on 7 June 2023

Students react after A-level Biology Paper 1 on 7 June 2023

Students react after A-level Biology Paper 3 on 21 June

Students react after A-level Biology Paper 3 on 21 June

Students react to A-level Chemistry Paper 2 on 19 June 2023

Students react to A-level Chemistry Paper 2 on 19 June 2023