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OCR Gateway Chemistry C4C5C6 - 13/06/13

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Original post by benwalters1996
ImageUploadedByStudent Room1371061128.587693.jpg Better orientation


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thanks dude, helpful! btw this guy's really good too, i think it's been pointed out already: http://www.youtube.com/watch?v=NTzFN98uWt4
Reply 381
Original post by AR-13
It was 104 for the exam, not sure about c/w, jus say i scraped an a?


your 102 - was a very high B
Scraped an A means 80 ums

102 + 80 = 182

For a B you need 280
so in this exam you need 280 - 182 = 98 .... this is only a C

For a A you need 320
so in the exam you need 320 - 182 = 138 ....this is only a A ..an average one

i would really push for the A mate

Ryan
Original post by ryanb97
your 102 - was a very high B
Scraped an A means 80 ums

102 + 80 = 182

For a B you need 280
so in this exam you need 280 - 182 = 98 .... this is only a C

For a A you need 320
so in the exam you need 320 - 182 = 138 ....this is only a A ..an average one

i would really push for the A mate

Ryan



If i got 40/48 in ca and 116/140 what would i need for an A? Raw mark wise?


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thanks; but last year, people could sit c1,c2,c3 in january for the new spec. so just wondering if they did it this year.

also; what ums will A* begin at and at what mark will that be? my guess is 52 being A*

cheers

tazzzzzzza
Reply 384
Original post by L'Evil Fish
I'm worried now :lol:

Hopefully full marks in C4/5... Then C6:mmm: what if I forget things after my C4 exam?


As long as you make an entrance like this you will be fine :

Spoiler

Reply 385
Original post by ryanb97
your 102 - was a very high B
Scraped an A means 80 ums

102 + 80 = 182

For a B you need 280
so in this exam you need 280 - 182 = 98 .... this is only a C

For a A you need 320
so in the exam you need 320 - 182 = 138 ....this is only a A ..an average one

i would really push for the A mate

Ryan


Thanks mate, i wud lov to get the a but i dnt thnk i no enough fr it, thnks btw

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Reply 386
Original post by AR-13
Thanks mate, i wud lov to get the a but i dnt thnk i no enough fr it, thnks btw

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One last thing, wat wud the raw mark be for 98 ums

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Original post by ryanb97
As long as you make an entrance like this you will be fine :

Spoiler



Do you have a question on neutralization? I want to practise one...
In biology, we're taught that fermentation does not occur in the presence of oxygen as normal respiration occurs, releasing CO2 and H2O.

In chemistry, we're taught that the presence of oxygen produces ethanoic acid. How do you reconcile these two ideas? :smile:


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Reply 389
Original post by BP_Tranquility
In biology, we're taught that fermentation does not occur in the presence of oxygen as normal respiration occurs, releasing CO2 and H2O.

In chemistry, we're taught that the presence of oxygen produces ethanoic acid. How do you reconcile these two ideas? :smile:


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Where does it say that for chemistry?
Reply 390
Starting to worry about C6 but should secure at least 40 marks on C4 and C5.
Original post by Knowing
Where does it say that for chemistry?

It says in my revision guide but also in the specification :smile: -
ImageUploadedByStudent Room1371066972.000296.jpg


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Original post by Knowing
Where does it say that for chemistry?


the ethanoic acid comes from the presence of oxygen. otherwise ethanol is produced when there is no oxygen.

i'm sure that's the case...can't find it in the revision guide though!
Reply 393
Original post by BP_Tranquility
It says in my revision guide but also in the specification :smile: -
ImageUploadedByStudent Room1371066972.000296.jpg


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Oh I get it. Fermentation results in ethanol, ​not ethanoic acid.
I literally feel so unprepared for this exam tomorrow, can someone please tell me how to work out the molar mass and the mass of each element (c5) thanks!
Reply 395
Original post by ChloBrown98
I literally feel so unprepared for this exam tomorrow, can someone please tell me how to work out the molar mass and the mass of each element (c5) thanks!


For the relative atomic mass of each element, look at the top number of their box in the periodic table.

To work out the molar mass, you work out the relative formula mass (basically add up all the relative atomic masses of all the elements in the formula/compound). This number is your molar mass (unit: grams/mole).

e.g. Molar mass of water.

Water = H2O
Atomic mass: H = 1, O = 16
Relative formula mass: (1 x 2) + 16 = 18

So the Molar mass of H2O is 18g/mol.

Hopefully this explains it :smile:
Original post by Knowing
For the relative atomic mass of each element, look at the top number of their box in the periodic table.

To work out the molar mass, you work out the relative formula mass (basically add up all the relative atomic masses of all the elements in the formula/compound). This number is your molar mass (unit: grams/mole).

e.g. Molar mass of water.

Water = H2O
Atomic mass: H = 1, O = 16
Relative formula mass: (1 x 2) + 16 = 18

So the Molar mass of H2O is 18g/mol.

Hopefully this explains it :smile:



Thank you! And it does explain it :smile: I actually get it now, thanks!!! :biggrin:
Can anyone explain how an ion-exchange resin works?
Original post by Daniel97g
Can anyone explain how an ion-exchange resin works?


Ions can be formed when electorns are lost or gained if this helps :smile: and I have no clue about what the 'resin' part is. Sorry :frown:
Reply 399
Original post by ChloBrown98
Thank you! And it does explain it :smile: I actually get it now, thanks!!! :biggrin:

You're welcome ^^

Original post by Daniel97g
Can anyone explain how an ion-exchange resin works?

Basically you have an "ion-exchange column", which is packed with small beads. When you flush sodium chloride solution through it (salt water basically), the sodium ions get attached to the ion-exchange resin/beads. When hard water (water with calcium and magnesium ions in) passes through the ion-exchange column, the calcium/magnesium ions in the water are swapped with the sodium ions in the column, because calcium is more attractive. Therefore, the sodium ions replace the calcium/magnesium ions in the hard water, softening it.

(If all the sodium ions have been replaced, you just flush the column with NaCl solution again, clearing away the Ca/Mg ions, and regenerating it with new sodium ions)
(edited 10 years ago)

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