The Student Room Group

Edexcel C3,C4 June 2013 Thread

Scroll to see replies

Reply 4661
Original post by Westeros
Integral of 2/(2x-1) you wrote as ln|2x-1| is this correct?
Also don't forget +C on your second line

It is because you have to divide by the differential within the brackets
Reply 4662
Original post by keromedic
I've no idea how to draw graphs from parametric equations. Eek


Don't worry, not on the specification.
Original post by orange94
Well I did! You right!

Unless anyone here objects to 1/3 being pulled out.

Here is what I did

ImageUploadedByStudent Room1371492088.213893.jpg


Posted from TSR Mobile


Cheers :smile: I had to put it in a weird form in terms of p using the limits, but got there eventually.

Posted from TSR Mobile
Original post by Jskalkut
It is because you have to divide by the differential within the brackets


Original post by PythianLegume
Do you think it isn't? One of us is missing something here.


Just testing :colondollar:


It involves treating it as (1/2)[sin(3x+x) + sin(3x-x)] It's a ridiculously difficult identity to see, and I doubt an actual C4 paper would have it.
Original post by Westeros
Just testing :colondollar:


Glad to be kept on my toes :wink:
Reply 4667


Manipulate the addition identities from C3 formulae sheet.

If you have sin3xcosx

Then sin (3x + x) = sin3xcosx + cos3xsinx (1)
then sin (3x - x) = sin3xcosx - cos3xsinx (2)

Therefore sin (3x + x) + sin (3x - x) = sin3xcosx (1) + (2)

therefore sin4x + sin2x = sin3xcosx

therefore just integrate sin4x + sin2x :smile:
(edited 10 years ago)
Original post by Kardy
Manipulate the addition identities from C3 formulae sheet.

If you have sin3xcosx

Then sin (3x + x) = sin3xcosx + cos3xsinx
then sin (3x - x) = sin3xcosx - cos3xsinx

Therefore sin (3x + x) + sin (3x - x) = sin3xcosx

therefore sin4x + sin2x = sin3xcosx

therefore just integrate sin4x + sin2x :smile:


I see! that was a hard one to identify okay,

did you do

sin3xcosx + cos3xsinx - ( sinxcosx - cos3xsinx)

sin3xcosx + cos3xsinx ?

then ?...

thank you
Reply 4669
can anyone tell me the basic rules for differentiation of ln and e^x
Reply 4670


Using the product to sum formula.

I've written it at the bottom on this sheet. The first one is the one that is relevant.

They are derived from the C3 trig. identities seen in the top right hand corner.(landscape)

Image (4).jpg
Reply 4671
having panic attack :frown:
Original post by fayled
Don't worry, not on the specification.


But it's in the book? Admittedly, just converting to Cartesian form and then drawing or drawing up a table of values before then drawing, but it's definitely in the book!
Does anyone know of a link to the current Edexcel A Level Mathematics Specification?
The one listed on their website currently points to a 404.
http://www.edexcel.com/migrationdocuments/GCE%20New%20GCE/UA024850%20GCE%20in%20Mathematics%20issue%202%20180510.pdf
Original post by otrivine
I see! that was a hard one to identify okay,

did you do

sin3xcosx + cos3xsinx - ( sinxcosx - cos3xsinx)

sin3xcosx + cos3xsinx ?

then ?...

thank you



Hi, is the answer -1/8cos4x - 1/4cos2x + c before putting the limits in?
Original post by amin666
having panic attack :frown:


Calm down, it'll be fine! Don't panic :smile:
Reply 4676
Original post by Fortitude
Hi, is the answer -1/8cos4x - 1/4cos2x + c before putting the limits in?



It is and you could have taken out the -1/2 as a constant. But that makes no difference.
Original post by Fortitude
Hi, is the answer -1/8cos4x - 1/4cos2x + c before putting the limits in?


Correct, can you show me please
Does anyone have a (link to)/(copy of) the current Edexcel A Level Mathematics Specification?
The one linked on their website currently points to a 404.
http://www.edexcel.com/migrationdocuments/GCE%20New%20GCE/UA024850%20GCE%20in%20Mathematics%20issue%202%20180510.pdf
Original post by MasterYi
It is and you could have taken out the -1/2 as a constant. But that makes no difference.


do you have working for that question by any chance :smile:

Quick Reply

Latest

Trending

Trending