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Edexcel C3,C4 June 2013 Thread

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Original post by Mallika
How do we find the area below the x-axis? I feel like I should know this but can't remember :frown:
Most questions ask to find the area enclosed by the curve, the x-axis and the co-ordinates!


Integration finds the total area, and area below the x-axis is considered 'negative area' therefore, if a graph has sections above and below the x-axis, you have to split it into integrals and take the modulus of the negative integral.
Original post by Exotica
Here is the marking scheme for June 2005
http://www.goffs.herts.sch.uk/goffsm4/mathsalevel%20docs/pbe%20c4/2005/C4%20June%202005%20mark%20scheme.pdf
On questions 4 I'm not able to understand how they got from the first line to the second.


1 - sin2x = cos2x

(cos2x)(3/2) = cos3x
Original post by otrivine
thank you :smile:

but how tan30=r/h :s-smilie:


Look at the attachment.
Does any1 knw how to do tht
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Reply 4824
Original post by LastOfUs
This is an integral of the form f'(x)[f(x)]^n. This means the answer is [f(x)]^n+1/n+1. So, you can write sin^2tcost as integral of cost[sint]^2.


that kinda makes sense, but i looked in the book and its actually one of the examples, oops!

thank you:smile:
Reply 4825
Original post by noeliah4
Does any1 knw how to do tht
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implicit differentiation,

so differentiate x normally, and y-> dy/dx, y^2 -> 2y dy/dx etc
Original post by noeliah4
Does any1 knw how to do tht
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Use your dy/dx, make it equal zero and that should start you :smile:
Original post by Fortitude
You might get an Oscar :wink:


its all about the MBE, OBEs at the moment
Reply 4828
why is a^x differentiated a^xlnA ?
Original post by LegendX
Look at the attachment.


i see and where did root 3/3 come from?
Original post by Tikara
why is a^x differentiated a^xlnA ?

y=a^x
lny=lna^x
lny=xlna
1/y * dy/dx = lna

dy/dx= ylna
dy/dx = a^x lna


:smile:
Reply 4831
Quick Question, How do you integrate cot 3x?
Original post by Tikara
why is a^x differentiated a^xlnA ?


See attachment
Original post by Fiyinad
Quick Question, How do you integrate cot 3x?


cot(x) integrates to ln(sinx) - it's in the formula book.
If you swap limits by substitution and you end up with limits that have a different size order, do you still go from high to low/top to bottom? For example 35 dx\int^5_3 \ dx turns into 42 du\int^2_4 \ du Is that right? Or should it be 24 du\int^4_2 \ du
Original post by otrivine
i see and where did root 3/3 come from?


Type tan30 into your calculator and then because its h2 you must square that value
Reply 4836
Original post by PythianLegume
cot(x) integrates to ln(sinx) - it's in the formula book.


Yh i get dat bit buh wah if cot3x came up in the exam? would it be 1/3ln[sin(3x)]?
Original post by MedMed12
its all about the MBE, OBEs at the moment


Well, you see I'm living in the past so what's current for me, is the past for you & what is current for you, is in the future for me, unfortunately this does not apply to exams :tongue:
solomon paper L. first question how is the least number of people in the queue mean that dn/dt = 0 what the hell? surely its n =0?
Reply 4839
Original post by noeliah4
Does any1 knw how to do tht
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Hopefully this makes sense


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