The Student Room Group
Uni students - Complete our survey >>
Uni students - Complete our survey >>
Uni students - Complete our survey >>

This discussion is now closed.

Check out other Related discussions

Girls Vs Boys MK VII

Scroll to see replies

Up

782
Original post by MathsNerd1
Oh the graphs? They annoyed me but it depend on what r is equal to?


Yeah :redface:

r = 1 + 2Cos(theta)

For example... It has the graph here, no scales, do I just draw it roughly?
782
Original post by L'Evil Fish
Yeah :redface:

r = 1 + 2Cos(theta)

For example... It has the graph here, no scales, do I just draw it roughly?


Well I was always taught to draw that function first and then sketch it to the polar co ordinate graph. But yeah draw a rough sketch but make sure they can see what it is too.

784
782
Original post by MathsNerd1
Well I was always taught to draw that function first and then sketch it to the polar co ordinate graph. But yeah draw a rough sketch but make sure they can see what it is too.

784


How do you mean?:redface:

784
782.
Original post by L'Evil Fish
How do you mean?:redface:

784


Okay have you sketched the original function first?
Original post by MathsNerd1
Okay have you sketched the original function first?


No :tongue: but now I have
784
Original post by L'Evil Fish
No :tongue: but now I have


Okay, so have they given you an example of how a function should be sketched into the polar coordinate form?

786
Original post by MathsNerd1
Okay, so have they given you an example of how a function should be sketched into the polar coordinate form?

786


788

No
786
788

I'm leaving polar co ordinates for tonight, tomorrow is area of a sector:colone:
Original post by L'Evil Fish
788

No


Okay well I'll explain an easy example for you to use on your question, quickly sketch the graph of sinx and basically once you've done this when you draw a polar co ordinate graph the line that is normally the x axis is called the initial line and the y axis will be your value as normal, so the polar graph will be measured in radians so when you start your sin function it starts at 0 so it does for the polar graph, then as you travel from 0-pi it goes from 0-1 and then back again and also you can't map your negative values on your original function to a polar graph so the shape should be a circle from 0-1.

Does that make sense?
788
790
Original post by MathsNerd1
Okay well I'll explain an easy example for you to use on your question, quickly sketch the graph of sinx and basically once you've done this when you draw a polar co ordinate graph the line that is normally the x axis is called the initial line and the y axis will be your value as normal, so the polar graph will be measured in radians so when you start your sin function it starts at 0 so it does for the polar graph, then as you travel from 0-pi it goes from 0-1 and then back again and also you can't map your negative values on your original function to a polar graph so the shape should be a circle from 0-1.

Does that make sense?


No :| :lol:

I'll start tomorrow with a fresh mind

Actually, yes! I get it :rofl: :biggrin: but not your explanation :tongue:
698 :biggrin:
696


Posted from TSR Mobile

Related discussions

Latest

Trending

Trending

Articles for you