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Maths edexcel c4 coordinate geometry

Stuck on q 7b !! Please help!!!:frown::frown:

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Reply 1
Original post by TenOfThem
ydx=ydxdtdt\displaystyle \int y dx = \displaystyle \int y \frac{dx}{dt} dt



How should I proceed? @@

Thanks


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Original post by Lamalam
Stuck on q 7b !! Please help!!!:frown::frown:

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The integral between curve and y axis would be given by (xdydt)dt\int(x\frac{dy}{dt})dt between limits t=2t=-\sqrt2 and t=2t=\sqrt2
Reply 3
Original post by brianeverit
The integral between curve and y axis would be given by (xdydt)dt\int(x\frac{dy}{dt})dt between limits t=2t=-\sqrt2 and t=2t=\sqrt2


why square root 2 and minus square 2?
:confused:

how would you approach this question?

sorry i know i am stupid ><

thanks!
Original post by Lamalam
why square root 2 and minus square 2?
:confused:

how would you approach this question?

sorry i know i am stupid ><

thanks!


The limits will be the values of t which make x=0, i.e the points on the y axis.
Reply 5
Original post by brianeverit
The limits will be the values of t which make x=0, i.e the points on the y axis.


Then isnt t= -1 and 1 ?
This is what I got when I draw the graph .
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Original post by Lamalam
Then isnt t= -1 and 1 ?
This is what I got when I draw the graph .
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x=0    t2=2    t=±2x=0\implies t^2=2\implies t=\pm\sqrt2
and the curve should be a parabola with horizontal axis y=0 and vertex at (-2,0)

Sorry, my mistake. I was looking at question 8 not question 7.
(edited 10 years ago)
Reply 7
Original post by brianeverit
x=0    t2=2    t=±2x=0\implies t^2=2\implies t=\pm\sqrt2
and the curve should be a parabola with horizontal axis y=0 and vertex at (-2,0)


I think you are looking at Q8
Original post by Lamalam
How should I proceed? @@

Thanks


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the question is asking about the area of the finite region bound by the loop so your limits are wrong. And also you can take only the upper area and then multiply by 2

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Original post by Lamalam
Then isnt t= -1 and 1 ?
This is what I got when I draw the graph .
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you can take from 0 to 1 and then multiply by 2 as it is symmetrical around the x axis.

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So that agrees with the book's answer?


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Reply 12
Original post by StUdEnTIGCSE
So that agrees with the book's answer?


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Yes :smile:

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Reply 13
Original post by StUdEnTIGCSE
So that agrees with the book's answer?


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When I looked at my answer again , I sstart wondering why I did this correctly @@ I put the two limits of intergral according to when x=0, its seems not reasonable @@,



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(edited 10 years ago)
Original post by Lamalam
When I looked at my answer again , I sstart wondering why I did this correctly @@ I put the two limits of intergral according to when x=0, its seems not reasonable @@,



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I started FP1 just the last month so its baffling me too.

I'm gonna investigate it tonight :cool::rolleyes::biggrin:
Original post by Lamalam
When I looked at my answer again , I sstart wondering why I did this correctly @@ I put the two limits of intergral according to when x=0, its seems not reasonable @@,

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I'm afraid this is beyond me :s-smilie::confused::frown:
Original post by TenOfThem
...


How is this possible?

Thank you

Integration paradox.png
Reply 17
Original post by StUdEnTIGCSE
How is this possible?

Thank you

Integration paradox.png

? I don't get what you mean
Original post by Lamalam
? I don't get what you mean


That would be the answer to your confusion...hopefully :wink:
Reply 19
Original post by StUdEnTIGCSE
That would be the answer to your confusion...hopefully :wink:


umm still a bit confused, would you please explain to me further?

thanks a lot!!

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