The Student Room Group

Disequation.

This is the disequation att_4806.jpg
There are my steps 1381761_169567723244686_831530729_n.jpg
The disequation's solution is x>1!
Reply 1
multiply both sides by 30, and expand...

the HCF of the LHS is 30, not 60
Reply 2
I did, but It again wrong.
1377323_169572943244164_1859014642_n.jpg
Reply 3
lets start simple.

doing what i suggested we get: 30(3x25+5x615+x310x330)\displaystyle 30(\frac{3x-2}{5}+\frac{5x-6}{15}+\frac{x-3}{10}-\frac{x-3}{30})

multiplying out we get:

6(3x2)+2(5x6)+3(x3)(x3)6(3x-2)+2(5x-6)+3(x-3)-(x-3)

=

6(3x2)+2(5x6)+2(x3)6(3x-2)+2(5x-6)+2(x-3)

expand...
(edited 10 years ago)
Original post by brunovona1998
I did, but It again wrong.
1377323_169572943244164_1859014642_n.jpg


You have put18x+12 as the first two terms in the numerator when it should be 18x-12
Original post by brunovona1998
This is the disequation att_4806.jpg
There are my steps 1381761_169567723244686_831530729_n.jpg
The disequation's solution is x>1!


Where did the word disequation come from? Why not use the accepted standard word for such a problem which is Inequality.
I thought I was entering a thread to do with a concept I've never heard of before ... aaaand it turns out to be an inequality. :nn:

Edit: Multiply the inequality by 30 and gather like terms.
(edited 10 years ago)

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