if i remember correctly, the question was:
x^2+ax+a=1, or
x^2+ax+a-1=0
if you want distinct solutions then by doing the discriminant you get:
a^2-4a+4 is equal or greater than 0....
or simpler:
(a-2)^2 is equal or greater than 0...
correct me if i'm wrong but this is always equal or greater than 0 so it is true for every real a...