Please could someone help me with this question. I just can't figure it out. Given that sinx=p/q, 0<x<pi/2 and p>0 and q>0, find cosec2x in terms of p and q.
Please could someone help me with this question. I just can't figure it out. Given that sinx=p/q, 0<x<pi/2 and p>0 and q>0, find cosec2x in terms of p and q.
Please could someone help me with this question. I just can't figure it out. Given that sinx=p/q, 0<x<pi/2 and p>0 and q>0, find cosec2x in terms of p and q.
cosec2x=1/sin2x so just find sinx and use the double angle identity to get sin 2x
Find a common denominator for the RHS and take the square root of the equality. Then substitute what you have for sin(x) and cos(x) into the original expression for cosec(2x).
Find a common denominator for the RHS and take the square root of the equality. Then substitute what you have for sin(x) and cos(x) into the original expression for cosec(2x).
don't forget to put "plus or minus" when you do a square root operation
Find a common denominator for the RHS and take the square root of the equality. Then substitute what you have for sin(x) and cos(x) into the original expression for cosec(2x).
Thank you so much for your help. I think I've got it now. so if cos2x=1-(p2/q2), then cosx=((q2-p2)1/2)/q2 (with some rearranging) and then substitute that along with p/q (=sinx) into 1/(2sinxcosx) and voila!