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C3 trig help

This is to do with trig identities. It's probably really simple but I'm having a mind block >< ImageUploadedByStudent Room1384610338.867098.jpg

Thankyou!


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Reply 1
replace tan with a well known combination of sin and cos...
Whenever I teach identities I encourage all students to have a sheet which:
(1) Lists all identities and subtle manipulations
(2) Methods in which to prove identities

You have some good advice in the post above.
Reply 3
Original post by the bear
replace tan with a well known combination of sin and cos...


I originally tried that and got an answer which is wrong. ImageUploadedByStudent Room1384611574.249642.jpg


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Original post by kendellex
I originally tried that and got an answer which is wrong. ImageUploadedByStudent Room1384611574.249642.jpg


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You didn't though

cosx/cosx = 1
Reply 5
Original post by kendellex
I originally tried that and got an answer which is wrong. ImageUploadedByStudent Room1384611574.249642.jpg



What did you do after the fraction line?
Original post by kendellex
I originally tried that and got an answer which is wrong. ImageUploadedByStudent Room1384611574.249642.jpg


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Would the last line not end up as (1+sin(2theta))/cos(2theta) ?
Reply 7
I just multiplied it by cosx - sinx to change it out of a fraction ImageUploadedByStudent Room1384612298.602975.jpg


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Reply 8
Original post by kendellex
I just multiplied it by cosx - sinx to change it out of a fraction ImageUploadedByStudent Room1384612298.602975.jpg




So where did your denominator go?
Original post by kendellex
I just multiplied it by cosx - sinx to change it out of a fraction ImageUploadedByStudent Room1384612298.602975.jpg


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But you haven't done that.

If I multiply the fraction 1/2 by 5 I dont get 5/10 I get 5/2.
Reply 10
I ended up with 1+sin theta/ 1- sin theta:confused:
Reply 11
Original post by kendellex
I originally tried that and got an answer which is wrong. ImageUploadedByStudent Room1384611574.249642.jpg


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Have you been given the answer to the question?
Reply 12
1+sin theta/ 1-sin theta
then multipliying the reciprocal to the numerator
so it goes 1+sin theta (x) 1/1-sin theta
then it ended up as (1-sin theta+sin theta-sin(squared)theta)
the -sin and +sin cancels out so I was left with (1-Sin(squared)Theta) Which is cos(squared)Theta.

Is this correct? I'm doing C3 too so I need help haha
Original post by brent_
1+sin theta/ 1-sin theta
then multipliying the reciprocal to the numerator
so it goes 1+sin theta (x) 1/1-sin theta
then it ended up as (1-sin theta+sin theta-sin(squared)theta)
the -sin and +sin cancels out so I was left with (1-Sin(squared)Theta) Which is cos(squared)Theta.

Is this correct? I'm doing C3 too so I need help haha


where does your
Unparseable latex formula:

\dfrac{1+\sin \theta}{1-\sin \theta}}

come from
Reply 14
Original post by TenOfThem
where does your
Unparseable latex formula:

\dfrac{1+\sin \theta}{1-\sin \theta}}

come from


I evaluated 1+sin/cos
1-sin/cos
And unfortunately ended up with that.
Original post by brent_
I evaluated 1+sin/cos
1-sin/cos
And unfortunately ended up with that.


You think that 1+sinθcosθ1sinθcosθ=1+sinθ1sinθ\dfrac{1+\frac{\sin \theta}{\cos \theta}}{1-\frac{\sin \theta}{\cos \theta}} = \dfrac{1+\sin \theta}{1-\sin \theta}


Where did the cosθ\cos \thetas go
Original post by kendellex
This is to do with trig identities. It's probably really simple but I'm having a mind block >< ImageUploadedByStudent Room1384610338.867098.jpg

Thankyou!


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Is it not just tan(theta + 45)

expand it out using the double angle formulas remembering that tan(45) = 1
Original post by Student10011
Is it not just tan(theta + 45)

expand it out using the double angle formulas remembering that tan(45) = 1


Yes, it is
Reply 18
Original post by Student10011
Is it not just tan(theta + 45)

expand it out using the double angle formulas remembering that tan(45) = 1


Thank you! I honestly forgot that rule >< I've got it now (:

ImageUploadedByStudent Room1384615387.453966.jpg


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Original post by kendellex
Thank you! I honestly forgot that rule >< I've got it now (:

ImageUploadedByStudent Room1384615387.453966.jpg


You may have solved this but - have you reflected on your error from earlier - do you know what you did wrong

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