Original post by Influence
16(1-T)(1-T)(1-L)(1-L) = 64L^2((1-T)^3)
Rearrange to find L
I've ended up with L = ((1-t)^0.5)/2 + 1. Is this correct?
Rearrange to find L
I've ended up with L = ((1-t)^0.5)/2 + 1. Is this correct?
Unfortunately not.
Show some working.
Original post by Influence
Is it L = 1/(2(1-t)^0.5) + 1?
If you add a copy of extra brackets then yes. There is a second solution too but I don't know whether you are supposed to realise that or not?
(edited 10 years ago)
Original post by Mr M
If you add a copy of extra brackets then yes. There is a second solution too but I don't know whether you are supposed to realise that or not?
mine does not look anything like that
Original post by TenOfThem
mine does not look anything like that
Perhaps you rationalised the denominator?
Original post by Influence
Where would we need the extra brackets?
L = 1/((2(1-t)^0.5) + 1)
Original post by Influence
I'm gonna guess that the second solution is -1/(2(1-t)^0.5) + 1? Can you show your working out please.
That isn't quite right. You show yours!
Original post by Mr M
That isn't quite right. You show yours!
I went wrong
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