C3 connected rates of change
Original post by The_Blade
If the side of the cube is x, what is the volume?
You are given dx/dt.
How is dV/dt related to dV/dx and dx/dt?
Original post by brianeverit
If the side of the cube is x, what is the volume?
You are given dx/dt.
How is dV/dt related to dV/dx and dx/dt?
You are given dx/dt.
How is dV/dt related to dV/dx and dx/dt?
Do I need the formula for volume to work out a cube and differentiate it? I don't know how to do that
Posted from TSR Mobile
Dy
dV/dt = dV/dx X dx/dt by chain rule
V=x^3 so dV/dx=3x^2
You try the rest
Original post by The_Blade
Do I need the formula for volume to work out a cube and differentiate it? I don't know how to do that
Posted from TSR Mobile
Posted from TSR Mobile
dV/dt = dV/dx X dx/dt by chain rule
V=x^3 so dV/dx=3x^2
You try the rest
Original post by krisshP
Dy
dV/dt = dV/dx X dx/dt by chain rule
V=x^3 so dV/dx=3x^2
You try the rest
dV/dt = dV/dx X dx/dt by chain rule
V=x^3 so dV/dx=3x^2
You try the rest
I got 48 but book says 72
Posted from TSR Mobile
Original post by The_Blade
dx/dt =-6
V=x^3
dV/dx=3x^2
dV/dt=dV/dx X dx/dt (chain rule used here)
=3x^2 X -6 (remember the cube side is decreasing at a rate of 6cm s^-1)
=-18x^2
When x=2
dV/dt=-18(2)^2
=-18(4)
=-72cm^3 s^-1
So the volume is decreasing at a rate of 72cm^3 s^-1.
I think your mistake was in the signs, so read the question carefully
.Original post by krisshP
dx/dt =-6
V=x^3
dV/dx=3x^2
dV/dt=dV/dx X dx/dt (chain rule used here)
=3x^2 X -6 (remember the cube side is decreasing at a rate of 6cm s^-1)
=-18x^2
When x=2
dV/dt=-18(2)^2
=-18(4)
=-72cm^3 s^-1
So the volume is decreasing at a rate of 72cm^3 s^-1.
I think your mistake was in the signs, so read the question carefully.
V=x^3
dV/dx=3x^2
dV/dt=dV/dx X dx/dt (chain rule used here)
=3x^2 X -6 (remember the cube side is decreasing at a rate of 6cm s^-1)
=-18x^2
When x=2
dV/dt=-18(2)^2
=-18(4)
=-72cm^3 s^-1
So the volume is decreasing at a rate of 72cm^3 s^-1.
I think your mistake was in the signs, so read the question carefully
.thank you very much
the problem was i differentiated x^3 to 2x^2 lol
Original post by krisshP
dx/dt =-6
V=x^3
dV/dx=3x^2
dV/dt=dV/dx X dx/dt (chain rule used here)
=3x^2 X -6 (remember the cube side is decreasing at a rate of 6cm s^-1)
=-18x^2
When x=2
dV/dt=-18(2)^2
=-18(4)
=-72cm^3 s^-1
So the volume is decreasing at a rate of 72cm^3 s^-1.
I think your mistake was in the signs, so read the question carefully.
V=x^3
dV/dx=3x^2
dV/dt=dV/dx X dx/dt (chain rule used here)
=3x^2 X -6 (remember the cube side is decreasing at a rate of 6cm s^-1)
=-18x^2
When x=2
dV/dt=-18(2)^2
=-18(4)
=-72cm^3 s^-1
So the volume is decreasing at a rate of 72cm^3 s^-1.
I think your mistake was in the signs, so read the question carefully
.Can you help me with this one. I don't know the formula for dl/dv
Posted from TSR Mobile
Original post by The_Blade
Let side length=x
V=x^3
dV/dt=2
dx/dV is needed as we want rate of change of x (dx), dependent variable, and we can work out easily volume V
dV/dx=3x^2
Spoiler
Original post by krisshP
Let side length=x
V=x^3
dV/dt=2
dx/dV is needed as we want rate of change of x (dx), dependent variable, and we can work out easily volume V
dV/dx=3x^2
V=x^3
dV/dt=2
dx/dV is needed as we want rate of change of x (dx), dependent variable, and we can work out easily volume V
dV/dx=3x^2
Spoiler
Thank you, you wonderful man
Posted from TSR Mobile
Quick Reply
Related discussions
- C3
- Senior Physics Challenge 2022
- Difficult Physics question (6 marks)
- Student accommodation at mary sturge- unite students, aston university
- Student accommodation at mary sturge- unite students, aston university
- HNC Electrical engineering
- High paying job
- Isaac Senior Physics Challenge 2024
- Animation at BU or MMU?
- Business
- Payslips
- Aqa biology help plz
- Psychology vs PGCSE vs Social work
- ULaw vs BPP vs City vs Brighton Uni Law (CPE)
- edexcel maths a level
- Edexcel A2 Mathematics: Core Mathematics C4 6666 01 - 22 June 2018 [Exam Discussion]
- Who's applied for Endcliffe accommodation 2023?
- Conversion to Economics?
- Orders of reaction
- rate Equation and Temperature
Latest
Last reply 1 minute ago
November 2023 Illegal Migration Intake Unit - Intake Response Team - Immigration OffiLast reply 3 minutes ago
Official London School of Economics and Political Science 2024 Applicant ThreadLast reply 4 minutes ago
yet to receive a woodhouse interviewLast reply 4 minutes ago
Official University of Sheffield Offer Holders Thread for 2024 entryLast reply 5 minutes ago
Woodhouse College applicants 2024Last reply 9 minutes ago
Goldmansachs Degree Apprenticeship 2024Posted 14 minutes ago
Tenancy transfer en-suite Stratford One London start June for Summer.Last reply 14 minutes ago
Official University of St Andrews Applicant Thread for 2024Last reply 15 minutes ago
Official University of York Offer Holders Thread for 2024 entryLast reply 17 minutes ago
Government Social Research - Research Officer Scheme 2024Last reply 18 minutes ago
Official: University of Bristol A100 2024 Entry ApplicantsTrending
Last reply 1 week ago
Edexcel A Level Mathematics Paper 2 unofficial mark scheme correct me if wrongMaths
71
Trending
Last reply 1 week ago
Edexcel A Level Mathematics Paper 2 unofficial mark scheme correct me if wrongMaths
71
