Hi Guys, how many different chemical environments are there in propan-2-ol? I believe there's 2- the CH3 groups and the COOH group but the answers say 3 and I can't seem to work out where the 3rd group is or what it even is lool.
Are you sure it's not the proton NMR, that would definitely have 3. But yeah, it looks like propan-2-ol would only have 2. Also, propan-2-ol does not contain a COOH group, which I'm sure you know :P
Hi Guys, how many different chemical environments are there in propan-2-ol? I believe there's 2- the CH3 groups and the COOH group but the answers say 3 and I can't seem to work out where the 3rd group is or what it even is lool.
Right, assuming this is an NMR question the answer is wrong. The OH proton is totally irrelevant as it will exchange with the D in the solvent and no peak will be observed. So from a 'actual molecule' point of view there are 3 different proton environments (methyl, CH(Me)2OH and OH) but from an NMR point of view only 2.
Right, assuming this is an NMR question the answer is wrong. The OH proton is totally irrelevant as it will exchange with the D in the solvent and no peak will be observed. So from a 'actual molecule' point of view there are 3 different proton environments (methyl, CH(Me)2OH and OH) but from an NMR point of view only 2.
Why wouldn't the OH peak show up? . Surely not every OH will have exchanged with solvent for the entire duration of the NMR sample being taken, so a singlet would show up..?
A quick database search shows there to be 3 peaks present
Why wouldn't the OH peak show up? . Surely not every OH will have exchanged with solvent for the entire duration of the NMR sample being taken, so a singlet would show up..?
A quick database search shows there to be 3 peaks present
EDIT: This is for proton NMR
Think about 2 things..... 1. NMR is very insensitive. You really don't get an idea for just how insensitive it is compared to e.g. mass spec 2. There are far more D's coming from the solvent than H's you put in from the sample. If they can equilibrate with each other then there will be a minute signal from the exchangeable protons.
H-D exchange takes place from the moment you mix the samples. No idea how fast the reaction is, but here they state
This exchange, which is catalyzed by acid or base, is very fast under normal conditions, since it is difficult to avoid traces of such catalysts in most experimental systems
so I suppose in typical situation H-D exchange can reach the equilibrium before the spectrum is recorded.
Think about 2 things..... 1. NMR is very insensitive. You really don't get an idea for just how insensitive it is compared to e.g. mass spec 2. There are far more D's coming from the solvent than H's you put in from the sample. If they can equilibrate with each other then there will be a minute signal from the exchangeable protons.
That's all very well, but I have a 2-propanol spectrum in front of me and there's a clear peak from the alcoholic proton at 2.16ppm.