(2x+1)Log 2 = 1 (2x + 1) = 1 / Log 2 rearranging gives x = 1.160964047 which is 1.16(3sf)
NOTE: I have just recently learnt this topic so please confirm to me whether my answer is right or if you dont have the mark scheme. Other people should attempt the question to confirm my answer or disapprove :/
(2x+1)Log 2 = 1 (2x + 1) = 1 / Log 2 rearranging gives x = 1.160964047 which is 1.16(3sf)
NOTE: I have just recently learnt this topic so please confirm to me whether my answer is right or if you dont have the mark scheme. Other people should attempt the question to confirm my answer or disapprove :/
That is what i have got now too, thanks for your help!
(2x+1)Log 2 = 1 (2x + 1) = 1 / Log 2 rearranging gives x = 1.160964047 which is 1.16(3sf)
NOTE: I have just recently learnt this topic so please confirm to me whether my answer is right or if you dont have the mark scheme. Other people should attempt the question to confirm my answer or disapprove :/
Your method is correct and just remember to ALWAYS work in a logical and methodical manner. Many people make mistakes when they try to do too much in their heads!