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How do I divide a number that cannot be divided?

Please help,

thanks:smile:
Reply 1
Is this a troll? It can't be divided.
I don't understand your question.

In what domain are we talking? Real, complex?

All real numbers can be divided...you just might not get a whole number.
How do I divide .2% of the calculus theorem?
Which theorem of calculus are you talking about? :holmes:

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Original post by King Leonidas
Please help,

thanks:smile:


You need to use Symbolic Mathematics.
Original post by majmuh24
Which theorem of calculus are you talking about? :holmes:

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I'm being totally serious, my maths is really bad I want to create my own theorem.
Reply 7
Define SS as the set of reals that cannot be divided. Then to divide do as you please king, it will be vacuously true, just don't kick me down a hole.
(edited 10 years ago)
Original post by ThatPerson
You need to use Symbolic Mathematics.


Indeed! Which method would you suggest - exponential ladders, squaring the ratio, or the Dalekian algorithm?

Original post by King Leonidas
I'm being totally serious, my maths is really bad I want to create my own theorem.


Dalek's already done that.

If {S:xS     x  cannot  be  divided} \{ S : x \in S \implies \ \text{x \ cannot \ be \ divided} \} , and aSa \in S, we can use Kaluza-Klein theory along with the topological 42 dimensional fractal self similarity between RS\mathbb R \to S

ab=ϑ2L(ab)\dfrac{a}{b} = \vartheta ^2 \cdot \mathcal{L} \left( \dfrac{a}{b} \right)

Where L \mathcal L denotes the Laplace Transform of ab\dfrac{a}{b} as a function of parameter t, which is given by L{f(t)}=0estf(t)\mathcal{L} \{ f(t) \} = \displaystyle\int_0^{\infty} e^{-st} \cdot f(t) where s is an arbitrary parameter.

Symbolic maths is the way to go :redface:
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(edited 10 years ago)
Reply 9
Original post by majmuh24
Indeed! Which method would you suggest - exponential ladders, squaring the ratio, or the Dalekian algorithm?

Dalek's already done that.


Gauss may have been the prince, but Dalek is the god of mathematics, period.
Original post by majmuh24
Indeed! Which method would you suggest - exponential ladders, squaring the ratio, or the Dalekian algorithm?



Dalek's already done that.

If {S:xS     x  cannot  be  divided} \{ S : x \in S \implies \ \text{x \ cannot \ be \ divided} \} , and aSa \in S, we can use Kaluza-Klein theory along with the topological 42 dimensional fractal self similarity between RS\mathbb R \to S

ab=ϑ2L(ab)\dfrac{a}{b} = \vartheta ^2 \cdot \mathcal{L} \left( \dfrac{a}{b} \right)

Where L \mathcal L denotes the Laplace Transform of ab\dfrac{a}{b} as a function of parameter t, which is given by L{f(t)}=0estf(t)\mathcal{L} \{ f(t) \} = \displaystyle\int_0^{\infty} e^{-st} \cdot f(t) where s is an arbitrary parameter.

I've created my own branch of maths too :redface:
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I see. The scary thing is that this makes as much sense to me as certain real maths.
I know a proof, but this page is too narrow to contain it. Soz.

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