Original post by MEPS1996
Solve the equation: sech^-1(x)=cosh^-1(x+1)
Do you do this by saying sech^-1(x)=cosh^(1/x) and then using the logarithmic forms of cosh^-1(x)
Do you do this by saying sech^-1(x)=cosh^(1/x) and then using the logarithmic forms of cosh^-1(x)
where is this questions from?
Original post by MEPS1996
Solve the equation: sech^-1(x)=cosh^-1(x+1)
Do you do this by saying sech^-1(x)=cosh^(1/x) and then using the logarithmic forms of cosh^-1(x)
Do you do this by saying sech^-1(x)=cosh^(1/x) and then using the logarithmic forms of cosh^-1(x)
Even easier than that.
Solve a quadratic equation. Make sure you reject one solution (why?).
Original post by MEPS1996
Solve the equation: sech^-1(x)=cosh^-1(x+1)
Do you do this by saying sech^-1(x)=cosh^(1/x) and then using the logarithmic forms of cosh^-1(x)
Do you do this by saying sech^-1(x)=cosh^(1/x) and then using the logarithmic forms of cosh^-1(x)
First I would examine the domains
For f(x)=arsech(x) Dom(f): 0<x<=1
For g(x)=arcosh(x+1) Dom(g): x+1>=1 => x>=0
So 0<x<=1
THen substittuting
arsec(x)=arcosh(1/x) => arcosh(1/x) =arcosh(x+1)
Using that arcosh(x) is monotone on x>=1
will be the equation without logarithm.
(edited 10 years ago)
Original post by Mr M
Even easier than that.
Solve a quadratic equation. Make sure you reject one solution (why?).
Solve a quadratic equation. Make sure you reject one solution (why?).
isn't the same as … have I missed something?
Original post by Mr M
Looks like it.
Oh dear - my statement is correct but irrelevant. I'll stop trying to think for today.
Original post by Phichi
Your first post has a horrible typo
Not seeing it. Sorry.
Original post by Smaug123
Oh dear - my statement is correct but irrelevant. I'll stop trying to think for today.
Thinking is overrated. Conducting your life in a vacant daze is the way to go.
Original post by Mr M
Not seeing it. Sorry.
I was misinterpreting what you wrote, not taking into context the equation in the OP. Thought you magically had proven this new identity haha, sorry.
Original post by Mr M
Even easier than that.
Solve a quadratic equation. Make sure you reject one solution (why?).
Solve a quadratic equation. Make sure you reject one solution (why?).
why is this?
Original post by MEPS1996
why is this?
What don't you understand?
Original post by Mr M
What don't you understand?
why cosh^-1(1/x)=cosh^-1(1+x)
Original post by MEPS1996
why cosh^-1(1/x)=cosh^-1(1+x)
That's the equation you've been asked to solve! (with the inverse sech rewritten)
Quick Reply
Related discussions
- hyperbolic function catenary problem
- Images of functions
- Ocr further maths core pure 2 5th june 2023
- Functions maths question
- AS logs help
- Alevel maths q help needed
- Domain and Range A level Maths
- Hardest topic in A level Further Maths
- differentiation help
- Functions and Mod Graphs HW Help Please!!
- A Level Maths Algebra and Functions
- cubic function, different ways of solving it?
- Lse Economics and Economic history…help please
- domains and ranges of graphs HELPPP (a-level maths)
- Maths Question
- Preparing for the MAT exam as a Scottish pupil doing Advanced Highers
- A Level Maths : Common Mistakes/misconceptions
- Further maths: Further Calculus
- Cournot Calculation help!
- a level math logs question
Latest
Trending
Last reply 1 day ago
Did Cambridge maths students find maths and further maths a level very easy?Last reply 2 weeks ago
Edexcel A Level Mathematics Paper 2 unofficial mark scheme correct me if wrongMaths
71
Trending
Last reply 1 day ago
Did Cambridge maths students find maths and further maths a level very easy?Last reply 2 weeks ago
Edexcel A Level Mathematics Paper 2 unofficial mark scheme correct me if wrongMaths
71
