Ok so if I know one half of the reaction and the overall reaction is there a method of finding the second half. Here is an example: 1st half equation = O2 + 4H+ + 4e- = 2H2O Overall reaction = CH3OH + 3/2O2 = 2H2O + CO2 Find the second half of the reaction its only one mark question so there is a quick method?
I suspect there is more information in the question that you omitted.
The way to do it is to identify in the overall equation what the other redox is. In this case CH3OH -> CO2. Then just create the half equation as usual: add water to balance O; add H+ to balance the H; add e- to the more +ve side.
I suspect there is more information in the question that you omitted.
The way to do it is to identify in the overall equation what the other redox is. In this case CH3OH -> CO2. Then just create the half equation as usual: add water to balance O; add H+ to balance the H; add e- to the more +ve side.
By multiplying 4 by 3/2. You have to do that to convert O2 to 3/2O2. You multiply everything in the equation, just like you do when adding half equations.