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C2- Binomial expansion

I can normally do questions to do with binomial expansion but can't seem to figure this one out. Any help would be appreciated. Part A is where I am stuck, part b shouldn't be too much of a problem if I know the value of a.
Original post by Super199
I can normally do questions to do with binomial expansion but can't seem to figure this one out. Any help would be appreciated. Part A is where I am stuck, part b shouldn't be too much of a problem if I know the value of a.


The binomial expansion is given in your formula book. Write down the first few terms and equate coefficients.
Reply 2
Original post by Mr M
The binomial expansion is given in your formula book. Write down the first few terms and equate coefficients.

Am I on the right lines? If so, I am not sure what to do next
Original post by Super199
Am I on the right lines? If so, I am not sure what to do next


They were just expecting you to write 1+nax+n(n1)a2x22=124x+270x2\displaystyle 1+nax+\frac{n(n-1)a^2x^2}{2}=1-24x+270x^2

Edit: Didn't realise this was Core 2. Use the value n = 16 provided.
(edited 9 years ago)
Reply 4
Original post by Mr M
They were just expecting you to write 1+nax+n(n1)a2x22=124x+270x2\displaystyle 1+nax+\frac{n(n-1)a^2x^2}{2}=1-24x+270x^2

Edit: Didn't realise this was Core 2. Use the value n = 16 provided.

Using what you said can I make a substitution for a? So a=-24/n.
Then sub that into n(n-1)a^2/2=270? Is that the way you are supposed to do it?
Original post by Super199
Using what you said can I make a substitution for a? So a=-24/n.
Then sub that into n(n-1)a^2/2=270? Is that the way you are supposed to do it?


That's the A2 way to do it. You are just expected to write down the first 3 terms of the expansion of (1+ax)16(1+ax)^{16}.
Reply 6
Original post by Mr M
That's the A2 way to do it. You are just expected to write down the first 3 terms of the expansion of (1+ax)16(1+ax)^{16}.

ah right that is a lot simpler. Thanks :smile:
Original post by Mr M
They were just expecting you to write 1+nax+n(n1)a2x22=124x+270x2\displaystyle 1+nax+\frac{n(n-1)a^2x^2}{2}=1-24x+270x^2

Edit: Didn't realise this was Core 2. Use the value n = 16 provided.


Isn't the (1+x)^n expansion in C2? It's mentioned in the textbook & the spec.
Original post by ThatPerson
Isn't the (1+x)^n expansion in C2? It's mentioned in the textbook & the spec.


Not in the OCR specification I'm used to. Others may differ.
Reply 9
Original post by ThatPerson
Isn't the (1+x)^n expansion in C2? It's mentioned in the textbook & the spec.

It is, I've never used it before. I asked my teacher and he said you can just use whatever method you prefer for AS anyway. Guess I will have to look into it a bit more.
Original post by Super199
It is, I've never used it before. I asked my teacher and he said you can just use whatever method you prefer for AS anyway. Guess I will have to look into it a bit more.


They have provided the value 16 so that you can use it if you choose to.
so after you get a do you plug it back into the first three terms?

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