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CCEA C4 Mathematics - 22nd May 2014

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Original post by stephen_mcgarry
Hi! I sure that's right for the point, but wasn't t out of the range to get these coordinates?


I used t=5π/4 which is smaller than 3π/2
Original post by Mr Tall
how did you do the last part of the vector question


Set the vector equal to the vector equation of the line, and showed that λ was equal to 2 for both i and j values.
Original post by TheWiseSalmon
I used t=5π/4 which is smaller than 3π/2


Oooh yeah! That's OK! Well done :biggrin:

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Just out of curiosity does anyone remember their answer for the volume of revolution question (the volume of the bowl)?
I thought my answer looked a bit odd, something along the lines of pi( 1/2e^2 + e + ?)
Original post by Rebecca-h
Just out of curiosity does anyone remember their answer for the volume of revolution question (the volume of the bowl)?
I thought my answer looked a bit odd, something along the lines of pi( 1/2e^2 + e + ?)


Can't remember my exact answer, but it was 24.0 to 3sf

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Original post by Mr Tall
but what if there was 2 points with gradient root2 in that domain? did you just have to pick one?


I really not sure what happens, I'm going to do it again now

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Original post by Rebecca-h
Just out of curiosity does anyone remember their answer for the volume of revolution question (the volume of the bowl)?
I thought my answer looked a bit odd, something along the lines of pi( 1/2e^2 + e + ?)


I think I got something like that, but it didn't say exact value so I just gave 24.0 cubic units
Original post by TheWiseSalmon
I think I got something like that, but it didn't say exact value so I just gave 24.0 cubic units


Yay same answer! :biggrin:

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Just done the last question again and it seems that there are two sets of coordinates, I cannot see how there can only be a "point"
The two points I got are (2pi,-4) and ((5pi-2)/2,-2sqrt2)
If anybody can correct me, or explain why it may be one point feel free, :smile: I would really appreciate it

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Can I post the full paper up as somebody is asking for the questions? But I can't send them in a private message? Will I be allowed to post the paper up?

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Original post by stephen_mcgarry
Can I post the full paper up as somebody is asking for the questions? But I can't send them in a private message? Will I be allowed to post the paper up?

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yep you can, it's done in one sitting!
Reply 31
Avatar for 1MacG
1MacG
The co-ordinate (2pi, -4) does not work, if you put your value for T which is equal to pi, back into your gradient equation, you'll see that it comes out as 0 and not root 2.
(edited 9 years ago)
Original post by 1MacG
The co-ordinate (2pi, -4) does not work, if you put your value for T which is equal to pi, back into your gradient equation, you'll see that it comes out as 0 and not root 2.


Doesn't that happen for 5pi/4 as well?

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Reply 33
Avatar for 1MacG
1MacG
Original post by stephen_mcgarry
Doesn't that happen for 5pi/4 as well?

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lol no

dy/dx = -4cos(5pi/4) / 2 - 2cos(5pi/2

= 2root2 / 2 = root2
(edited 9 years ago)
Original post by 1MacG
lol no

dy/dx = -4cos(5pi/4) / 2 - 2cos(5pi/2

= 2root2 / 2 = root2


Hmm, isn't dy/dx = -4sint/(2-2cos2t)

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OK so here is the full paper


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1400767632036.jpg37.4KB
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1400767751242.jpg45.7KB
Original post by stephen_mcgarry
OK so here is the full paper


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In case you can't see, question 3 is the integral between 3 and 2

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Original post by stephen_mcgarry
Hmm, isn't dy/dx = -4sint/(2-2cos2t)

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Hey, could you post the paper please? :smile:

Edit: I see your post now, thanks :smile:
(edited 9 years ago)
Original post by GingerCodeMan
Hey, could you post the paper please? :smile:

Edit: I see your post now, thanks :smile:


Haha that's OK, spent ages trying to send it in pm, gave up and put it up here :biggrin:

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Reply 39
Avatar for 1MacG
1MacG
Original post by stephen_mcgarry
Hmm, isn't dy/dx = -4sint/(2-2cos2t)

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sorry just a typo error, but it works out as root2

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