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Original post by Mutleybm1996


Where did you get m from? The formula we're given is T=2pi*root(L/g).

the gradient of what?
Original post by Mutleybm1996

https://www.youtube.com/watch?v=8-CUDWndI74 stop at 3:32, it says g=4pi^2m.
Original post by Mutleybm1996
You'll be ok! How did you find unit 1?

Physics teachers are generally pretty rubbish at explaining things, Biology and Chemistry all the way :biggrin:


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Unit one was shocking! OH DEAR OH DEAR OH DEAR ( pretty sure I am going to have to retake next year Curse Gove and his removal of the january exams) this video did cheer me up about it though
https://www.youtube.com/watch?v=DIkSSqr1gfc

I've got to say maths teachers are clearly the best kind of teachers. GO MATHS DEPARTMENT
Original post by LimbuRonit
https://www.youtube.com/watch?v=8-CUDWndI74 stop at 3:32, it says g=4pi^2m.


Pat 1:07 it says g= (L*4pi^2)/T^2 though!!! :/
Original post by Carla Huynh
Pat 1:07 it says g= (L*4pi^2)/T^2 though!!! :/


Ah I see what they've done. They've plotted L against T^2 so the gradient of this is m and therefore g=4pi^2*m
Original post by Carla Huynh
Pat 1:07 it says g= (L*4pi^2)/T^2 though!!! :/


ImageUploadedByStudent Room1402179938.081039.jpg


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Original post by Carla Huynh
Ah I see what they've done. They've plotted L against T^2 so the gradient of this is m and therefore g=4pi^2*m


See above


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Reply 68


The gradient squared?! Why?
FFs what the hell is going on!!!!!! my head is going to explode !!!!:eek:


Ok now I'm confused. That's in the form T^2=
what would it be in the form g=?
Original post by LimbuRonit
FFs what the hell is going on!!!!!! my head is going to explode !!!!:eek:


Haha yup me too! Thought I understood it until everyone mentioned gradients! :/
Reply 73
Original post by Carla Huynh
The gradient squared?! Why?


Rearrange the equation and that's what you get, the gradient being of the graph T on the y axis, rootL on the x

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Original post by Carla Huynh
Haha yup me too! Thought I understood it until everyone mentioned gradients! :/


Can't find a single perfectly explained video!!!! on pendulum :angry::angry::angry:
Original post by emfp21
Rearrange the equation and that's what you get, the gradient being of the graph T on the y axis, rootL on the x

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Oh ok I thought it would make more sense to plot T^2 against L so the. It would just be m not m^2...maybe I'm not sure!
Reply 76
Original post by Carla Huynh
Oh ok I thought it would make more sense to plot T^2 against L so the. It would just be m not m^2...maybe I'm not sure!


Depends on what they ask in the exam. Could be either

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Guys, click on the link below and scroll to the bottom, there are questions and answers for predicted section C questions

http://matthew-arnold.tmp.synergy-learning.com/course/view.php?id=62
Also guys, just from judging by the G491 paper, I think there is an awfully good chance a question involving the estimation of wavelengths from different parts of the electromagnetic spectrum, so maybe give that a quick look?
Reply 79
Original post by shloke123
Also guys, just from judging by the G491 paper, I think there is an awfully good chance a question involving the estimation of wavelengths from different parts of the electromagnetic spectrum, so maybe give that a quick look?


Would you mind explaining that?? All we got told was radio waves have high wavelengths, then as you go through the spectrum to gamma wavelengths decrease due to higher frequency

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