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OCR PHYSICS B G492~ 9rd June 2014~ AS Physics

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Reply 300

Knowing

Original post by Minecraft27

It was 24.

1kWh is equivalent to 3.6MJ of energy. The battery's capacity was 16kWh => 57.6MJ. The car can travel for 120km/80km = 1.5hours = 90 minutes = 5400 seconds.

So Power = Energy/Time = 57,600,000/5,400 = 10666.667...Js^-1

So the answer should be 10.7kW.

Reply 301

DanielCook95

Original post by CrystalPlanet

I think you'd only lose one mark (it was a two mark question if I remember correctly); you stated that you had to multiply the length by two, so you'll probably get a mark for that.

I really hope so. Due to this I'm really hoping they allow an ECF for the part where you had to calculate the percentage increase of the frequency if the flute was not extended.. :colondollar:

Thank you for your reply as well!

Reply 302

DanielCook95

I'm sure the power question was along the lines of this:

*Table stating maximum power is 49kW and battery capacity is 16kWh*

"Peugot state that the range of the car is 120km when travelling at a constant speed of 80kmh^-1 and the battery is fully charged initially, show that the power provided is significantly less than the figure given in table x?"

Reply 303

RoryV

I also got 10.7kW for the car power question

Sent from my iPhone using Tapatalk

Reply 304

DomStaff

Original post by DanielCook95

I really hope so. Due to this I'm really hoping they allow an ECF for the part where you had to calculate the percentage increase of the frequency if the flute was not extended.. :colondollar:

Thank you for your reply as well!

There is no need for ECF. That part required nothing from any other parts.

Reply 305

DanielCook95

Original post by DomStaff

There is no need for ECF. That part required nothing from any other parts.

Thinking about it now I don't even think that I used it haha! Do you mind me asking what you got for the answer to the percentage part? :redface:

Reply 306

Knowing

Original post by PsychoPanda

I got 10^-6 for finger cross section. And I got 3 % for the temperature question, tbh in not so sure about the 3% but the cross sectional area of a finger is definitely 10^-6

Posted from TSR Mobile

I disagree: my finger's cross-sectional area is about 1cm x 1cm, which is 0.01m x 0.01m = 1x10^-4 m^2

10^-6 would mean that your finger is 1mm wide and thick.

Reply 307

DomStaff

Original post by PsychoPanda

I got 10^-6 for finger cross section. And I got 3 % for the temperature question, tbh in not so sure about the 3% but the cross sectional area of a finger is definitely 10^-6

Posted from TSR Mobile

I disagree, also. The diameter of my finger is approx 1cm. I have skinny fingers, so I am at the lower end of the spectrum. This gives me a x-sectional area in somewhere like 7.something * 10^-5, therefore approximately 10^-4.

Reply 308

DomStaff

Original post by DanielCook95

Thinking about it now I don't even think that I used it haha! Do you mind me asking what you got for the answer to the percentage part? :redface:

2.6%

It is just root298 - root283 divided by root283. Then multiplied by 100.

Reply 309

DanielCook95

Original post by Knowing

I disagree: my finger's cross-sectional area is about 1cm x 1cm, which is 0.01m x 0.01m = 1x10^-4 m^2

10^-6 would mean that your finger is 1mm wide and thick.

I concur..

Reply 310

DanielCook95

Original post by DomStaff

2.6%

It is just root298 - root283 divided by root283. Then multiplied by 100.

Haha that's a relief, I got that too. I did use the frequency but I think I ended up putting a line through it because I realised that it wasn't needed. Thank you!

Reply 311

DomStaff

Original post by DanielCook95

Haha that's a relief, I got that too. I did use the frequency but I think I ended up putting a line through it because I realised that it wasn't needed. Thank you!