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I can't figure out the answer to this question from a physics workbook. Any help???
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Original post by Ngaden76
I can't figure out the answer to this question from a physics workbook. Any help???



You need to post the whole question including the diagram.
Reply 2
Avatar for ndnd_ndnd
ndnd_ndnd
OP
10
Original post by Stonebridge
You need to post the whole question including the diagram.

That's what I'm talking about!! There's no diagram. :\ !!
Original post by Ngaden76
That's what I'm talking about!! There's no diagram. :\ !!


No diagram = no answer.

You can't answer the question because it is incomplete. It refers to something "below", which isn't there. It will be a diagram showing a force and a distance of that force from a pivot.
The moment of the force is equal to the force times the (perpendicular) distance from the pivot.
More than that we cannot say as we don't have the actual values.
Is that the entire question? :confused:
Reply 5
Avatar for lerjj
lerjj
13
moment= force X perpendicular distance

if force is not acting perpendicular to the pivot, then you need to resolve it (your equation becomes m=Fs sin(θ) m = Fs\text{ sin}(\theta) ).

Obviously you can't actually answer the question though, because you don't have the diagram it's asking about. :mad:

If you know this stuff, just leave it. If you aren't feeling confident I'm sure you can find some example questions online. Or draw some.

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