C3-Trig

Mm need some help with the following question.
I don't know what to do next.

Cheers me dears :smile:

Mm need some help with the following question.
I don't know what to do next.

Cheers me dears :smile:

You have got following

\displaystyle \frac{1-\cos \theta}{\sin \theta}

Multiply both the numerator and the denominator by

1+\cos \theta

In the numerator use the identity of

(1-\cos \theta)(1+\cos \theta)=1-\cos^2 \theta=\sin^2 \theta

\sin \theta

will be cancelled
then
divide both the numerator and denominator by

\sin \theta

You have got following

\displaystyle \frac{1-\cos \theta}{\sin \theta}

Multiply both the numerator and the denominator by

1+\cos \theta

In the numerator use the identity of

(1-\cos \theta)(1+\cos \theta)=1-\cos^2 \theta=\sin^2 \theta

\sin \theta

will be cancelled
then
divide both the numerator and denominator by

\sin \theta

Small correction in the last step

divide both the numerator and denominator by

\cos \theta

Small correction in the last step

divide both the numerator and denominator by

\cos \theta

OK. Thanks

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