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Sketching graphs

The question says sketch the curve: y=x^3-6x^2+9x
I drew it with solutions 0 and 3,3.
The next question asks:
Using your answer to (b) (the last question) sketch on a separate diagram the curve with equation: y=(x-2)^3-6(x-2)^2+9(x-2) showing the coordinates of the points at which the curve meets the x axis. I don't know where to begin or what the answer has to do with the previous question.

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Original post by Year11guy
The question says sketch the curve: y=x^3-6x^2+9x
I drew it with solutions 0 and 3,3.
The next question asks:
Using your answer to (b) (the last question) sketch on a separate diagram the curve with equation: y=(x-2)^3-6(x-2)^2+9(x-2) showing the coordinates of the points at which the curve meets the x axis. I don't know where to begin or what the answer has to do with the previous question.


You have drawn f(x) and now need to draw f(x-2)

Have you done Graph Transformations?
Reply 2
Original post by Year11guy
The question says sketch the curve: y=x^3-6x^2+9x
I drew it with solutions 0 and 3,3.
The next question asks:
Using your answer to (b) (the last question) sketch on a separate diagram the curve with equation: y=(x-2)^3-6(x-2)^2+9(x-2) showing the coordinates of the points at which the curve meets the x axis. I don't know where to begin or what the answer has to do with the previous question.


You do notice the similarity don't you?
Reply 3
Original post by TenOfThem
You have drawn f(x) and now need to draw f(x-2)

Have you done Graph Transformations?



Original post by BabyMaths
You do notice the similarity don't you?


So it's the same graph but just 2 units to the right? Would you get the same answer from expanding because that's what I began doing.
Reply 4
Original post by Year11guy
So it's the same graph but just 2 units to the right? Would you get the same answer from expanding because that's what I began doing.


Yes, you could expand and so on but that would take considerably longer and you wouldn't be using your last answer as required by the question.
Original post by Year11guy
So it's the same graph but just 2 units to the right? Would you get the same answer from expanding because that's what I began doing.


You would get the same answer, yes

But you would be wasting time :frown:
Reply 6
Original post by Year11guy
So it's the same graph but just 2 units to the right? Would you get the same answer from expanding because that's what I began doing.


Original post by TenOfThem
You would get the same answer, yes

But you would be wasting time :frown:


How would I find the equations of the asymptotes of y=3/x+2
Original post by Year11guy
How would I find the equations of the asymptotes of y=3/x+2


http://www.thestudentroom.co.uk/showthread.php?t=2873737

What do you know about asymptotes?
Reply 8
Original post by TenOfThem


y=3/(x+2)

its a line that is approached but not touched by the curve
Original post by Year11guy
y=3/(x+2)

its a line that is approached but not touched by the curve


Can I ask the context of your question - are you actually in Year 11
Reply 10
Original post by TenOfThem
Can I ask the context of your question - are you actually in Year 11


Lol, this was made when I was in year 11, I'm doing AS
Original post by Year11guy
Lol, this was made when I was in year 11, I'm doing AS


Remember to label threads as sixth form then :smile:


So - do you know what value x cannot take?
Reply 12
Original post by TenOfThem
Remember to label threads as sixth form then :smile:


So - do you know what value x cannot take?


0?
Original post by Year11guy
0?


Why would that be?

If x = 0, y = 3/2

I see no problem with that
Reply 14
Original post by TenOfThem
Why would that be?

If x = 0, y = 3/2

I see no problem with that


-2 sorry
Original post by Year11guy
-2 sorry


So you know one asymptote x=-2


Now you need the y asymptote

Can you see a value that y cannot =
Reply 16
Original post by TenOfThem
So you know one asymptote x=-2


Now you need the y asymptote

Can you see a value that y cannot =


Does it have to be a whole number? Is there a way to calculate it?
Original post by Year11guy
Does it have to be a whole number? Is there a way to calculate it?


There are a number of ways - have you been shown any

Simply spotting in this case
Splitting the numerator
Dividing by x
Reply 18
Original post by TenOfThem
There are a number of ways - have you been shown any

Simply spotting in this case
Splitting the numerator
Dividing by x


I haven't really learned about this. I was shown the spotting one. Which is the short/easiest?My exam board is edexcel if there's a specific one I must know
Original post by Year11guy
I haven't really learned about this. I was shown the spotting one. Which is the short/easiest?My exam board is edexcel if there's a specific one I must know


You can use any

Clearly "spotting" is the shortest - so if you have been shown that use that

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